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Aleonysh [2.5K]
3 years ago
6

(WILL GIVE BRAINLIEST, THANKS, AND 5-STAR RATING)

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

Step-by-step explanation:

68°

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!!! 25 POINTS HELP PLS
weqwewe [10]

Answer:

Option (3)

Step-by-step explanation:

Given functions are,

f(x) = \frac{1}{4^x}

g(x) = log(2x)

By using a graphing utility we can draw the graphs of the given system of equations.

Common points of the graph will be the solutions of the equations,

From the graph attached,

Solution of the functions is → (0.937, 0.273)

                                             → (0.9, 0.3)

Option (3) will be the answer.

3 0
3 years ago
The cost function for a backpack company is C(x) = 23x + 3900 and the revenue function is R(x) = 35x. Identify the Fixed cost
GarryVolchara [31]
This is the awnser have a safe night

3 0
3 years ago
Please help me! Thank you so much!<br><br> Please show ALL work!
LenKa [72]
You estimate 16 and 2 so it is 20+2=22
8 0
4 years ago
Find the zeros of f(x)=-x^2+6x+27
lara31 [8.8K]

Answer:

Zeroes of this function are -3 and 9.

Step-by-step explanation:

Using quadratic formula we have:

(-6 +- \sqrt{6^{2}-4(-1)(27) }) / 2(-1)

= -3, 9

4 0
3 years ago
9. Consider the circles with the following equations:
kenny6666 [7]

Answer with Step-by-step explanation:

We are given that

x^2+y^2=(\sqrt 2)^2

(x-3)^2+(y-3)^2=32=(4\sqrt 2)^2

Compare with the equation of circle

(x-h)^2+(y-k)^2=r^2

Where center of circle=(h,k)

r=Radius of circle

a.Center of circle=(0,0)

Radius=\sqrt 2 units

Center of second circle=(3,3)

Radius of second circle=4\sqrt 2 units

b.Distance formula:\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Using the formula

The distance between the centers of two circle

=\sqrt{(3-0)^2+(3-0)^2}=3\sqrt 2

Hence, the distance between the centers of two circle =3\sqrt 2 units.

c.

Substitute x=-1 and -1

1+1=2=

(1-3)^2+(1-3)^2=32

The circle must be tangent because there is just one point (-1,-1) is common in both circles and satisfied the equations of circle.

8 0
3 years ago
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