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jek_recluse [69]
2 years ago
6

!!! 25 POINTS HELP PLS

Mathematics
1 answer:
weqwewe [10]2 years ago
3 0

Answer:

Option (3)

Step-by-step explanation:

Given functions are,

f(x) = \frac{1}{4^x}

g(x) = log(2x)

By using a graphing utility we can draw the graphs of the given system of equations.

Common points of the graph will be the solutions of the equations,

From the graph attached,

Solution of the functions is → (0.937, 0.273)

                                             → (0.9, 0.3)

Option (3) will be the answer.

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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
Give your answer in minutes.
Illusion [34]
In an hour there are 60 minutes.

6:38 PM + 22minutes = 7 PM
From 7 PM to 7:23 PM there are 23 minutes

So, (23 + 22) minutes = 45 minutes.
5 0
2 years ago
Read 2 more answers
Explain the steps necessary to convert a quadratic function in standard form to vertex form
SIZIF [17.4K]

Answer:

See below.

Step-by-step explanation:

Here's an example to illustrate the method:

f(x) = 3x^2 - 6x + 10

First divide the first 2 terms by the coefficient of x^2 , which is 3:

= 3(x^2 - 2x) + 10

Now  divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form

(x - b/2)^2 - b/2)^2  (where b = 2) , which will be equal to x^2 - 2x in a different form.

= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x  + 1^2  and we have to make it equal to x^2 - 2x)

= 3 [(x - 1)^2 -1 ] + 10

= 3(x - 1)^2 - 3 + 10

= <u>3(x - 1)^2 + 7 </u><------- Vertex form.

In general form the vertex form of:

ax^2 + bx + c  = a [(x - b/2a)^2 - (b/2a)^2] + c .

This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.

3 0
3 years ago
Read 2 more answers
Solve using the quadratic formula<br><br> x² - 12x + 36=0
motikmotik

Answer:

6

Step-by-step explanation:

(-12)^2-4*1*36=0

144-144=0

x= -(-12)/2*1=

12/2=

6

x=6

4 0
3 years ago
Sales Tax
kicyunya [14]

Answer: $2.40

Step-by-step explanation:

$60.00 x .04 = $2.40

8 0
2 years ago
Read 2 more answers
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