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3 years ago

Cual es la fracción de 0.7

Mathematics

1 answer:

kakasveta [241]3 years ago

8 0

Answer:

La fracción de 0.7 es 7/10

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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

3 years ago

Six times a number is three thousand six hundred. what is the number?

Likurg_2 [28]

Im prety sure its 600

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Which of the following correctly translates "quotient"?

tatiyna

Answer:

A quotient is division.

Step-by-step explanation:

Addition is sum

Division is quotient

muultiplication is product

subtraction is difference

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2 years ago

The volume of a right square pyramid is 7 yd.. If the lengths of the sides of the base are multiplied by 5 and the height does n

ZanzabumX [31]

Answer:

Explanation

D

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2 years ago

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How to find upper and lower bound of a definite integral given an unknown equation?

worty [1.4K]

Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this

$\int\limits^6_1 t^{2} - 6t + 11dt$

So, i integrate this,
$( \frac{t^{3} }{3} - 3t^{2} + 11t) \int\limits^6_1$

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4

4 0

3 years ago