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3 years ago

If a triangle has two angles that measure 25 degrees each, what must be the measure of the

Mathematics

2 answers:

Vinil7 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Add up the two known angle measurements. All you have to know is that all of the angles in a triangle always add up to 180°. This is true 100% of the time. So, if you know two of the three measurements of the triangle, then you're only missing one piece of the puzzle. The first thing you can do is add up the angle measurements you know. In this example, the two angle measurements you know ...

Subtract this number from 180°. The angles in a triangle add up to 180°. Therefore, the remaining an…

timurjin [86]3 years ago

3 0

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Jack had 4 hours of school. He spent 45 minutes in the library and 12 hour on a science lecture and had a lunch break of 25 minu

andre [41]

Answer:

$\dfrac{10}{4} \ hour$

Step-by-step explanation:

Given that :

Jack had 4 hours of school.

He spent 45 minutes in the library

1/2 hour on a science lecture and;

had a lunch break of 25 minutes

The objective is to determine how much time is left for the school to get over and we are to write the answer as a fraction.

In order to do that, we will have to convert the minutes into hours,

we all know that; 60 minutes = 1 hour.

Then,

45 minutes = (45/60)hour = 3/4 hour

25/60 minutes = 1/4 hour

Therefore, the amount of time left for the school to get over is:

= $4 - (\dfrac{3}{4}+\dfrac{1}{2}+ \dfrac{1}{4})$

= $\dfrac{16-(3+2+1)}{4}$

= $\dfrac{16-6}{4}$

= $\dfrac{10}{4} \ hour$

7 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$