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Paha777 [63]
3 years ago
11

PLEASE HELP! I REALLY NEED IT

Mathematics
2 answers:
wolverine [178]3 years ago
8 0
I can’t really help you I’m sorry I don’t really know the answer but I do need points thank you byeAdios
Ksenya-84 [330]3 years ago
6 0

Answer:

i think its like this:

Step-by-step explanation:

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Which ray is oppisite to ED
Lerok [7]

You don't have a picture here , but try to see if any ray are maybe parralell .

Hope this helps!

3 0
3 years ago
Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research
kolbaska11 [484]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

Yes the researcher can  conclude that the supplement has a significant effect on cognitive skill

b

d =  0.5778

c

The result of this hypothesis test shows that there is sufficient evidence to  that the supplement had significant effect.The measure of effect size is  large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

  The sample size is  n=16

    The sample mean is  M  =  50.2

    The standard deviation is \sigma  = 9

    The  population mean is  \mu =  45

     The level of significance is  \alpha =  0.05

The null hypothesis is H_o  \mu =45

The alternative hypothesis is H_a  \mu \ne 45

Generally the test statistics is mathematically represented as

          z =  \frac{M -  \mu}{\frac{\sigma}{\sqrt{n} } }

=>       z =  \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }

=>       z =  2.31

Generally the p-value is mathematically represented as

     p-value  =  2 *  P(Z >  z )

      p-value  =  2 *  P(Z >  2.31 )

From the z-table  

      P(Z >  2.31 ) = 0.010444

=>     p-value  =  2 *  0.010444

=>     p-value  =  0.021

From the obtained values we see that p-value <  0.05

 Decision Rule

 Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

    d =  \frac{M  -  \mu}{\sigma }

=>  d =  \frac{50.2 -45}{9 }

=>  d =  0.5778

3 0
4 years ago
7x5=20+8+<br> Fill in the missing number to make the equation true
antoniya [11.8K]
Answer: 7

step-by-step:
okay so first you do 7*5 which is 35 and 20+8 which is 28

then you get 35=28+x (the x is the ‘missing number’)

to find x you subtract 28 from both sides to keep the equation balanced

35-28=28-28+x

so 35-28 is 7 and 28-28 is 0 so then you have 7=x and your answer is 7

you’re doing algebra but instead of using variables your teacher is saying find the ‘missing number’ haha
3 0
3 years ago
Which of the following would not be a possible function for f (x) and g(x) such that f of g of x is equal to 6 over the quantity
Aleonysh [2.5K]

Option C is correct. the functions that would not be a possible function for f (x) and g(x) are f(x) = \frac{4}{x^2+2} and g(x) = x

Given the composite function

f(g(x))=\frac{6}{x^2+3}

We are to look for two functions f(x) and g(x) that will not give the same function

Using trial and error,

If f(x) = \frac{4}{x^2+2} and g(x) = x

Determine the f(g(x)) for this function

f(g(x)) = f(x)

This is gotten by simply replacing x with x in f(x). This will return back the function f(x) making this the right choice.

f(g(x)) = \frac{4}{x^2+2}

Since,  \frac{4}{x^2+2} \neq \frac{6}{x^2+3}, hence the functions that would not be a possible function for f (x) and g(x) are f(x) = \frac{4}{x^2+2} and g(x) = x

Learn more here: brainly.com/question/3256461

7 0
3 years ago
Raise r to the 7th power, then double the result
Minchanka [31]

Answer:

\huge\boxed{\bf\:2r^{7}}

Step-by-step explanation:

Let the variable be taken as 'r'.

Then, by raising it to the 7th power, we'll get the result as \downarrow

 \sf\:Raise \: r \: to \: the \: 7^{th} \: power = r \: with \: 7 \: as \: its \: exponent.\\\\\sf\:Then,\\\dashrightarrow \underline{\bf\:r \: ^{7}}

Now, by doubling the result....

\sf\:To \: double \: the \: result = multiply \: the \: result \: by \: 2.\\\\\sf\:Then,\\\dashrightarrow \sf\:r \: ^{7} \\=\boxed{\bf\: 2r\:^{7}}

\rule{150pt}{2pt}

8 0
2 years ago
Read 2 more answers
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