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Yuki888 [10]
3 years ago
6

What happened on September 11, 2001?

Mathematics
2 answers:
Radda [10]3 years ago
3 0

Answer:

On 11 September 2001 (known as 9/11 in America), Islamist extremists hijacked four planes that were flying above the US. Two of them were flown into the twin towers of the World Trade Center in New York. Another was crashed into the Pentagon, the top military building in the capital city, Washington DC.

Step-by-step explanation:

vfiekz [6]3 years ago
3 0

Answer:

On the morning of September 11, 2001, 19 al-Qaeda terrorists hijacked four commercial passenger jet airliners, intentionally crashing two into the World Trade Center in New York City. The hijackers crashed a third airliner into the Pentagon. The fourth plane crashed in a field near Shanksville, Pennsylvania.

Hope this helps :)

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What is 1,729 times 308?
Black_prince [1.1K]
532,532 would be the answer
4 0
3 years ago
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery servic
sineoko [7]

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.

100 - 35 = 65%.

So P(B) = 0.65

Service 2 has a record of 2.0% of packages being delivered late.

This means that P(A|B) = 0.02

Probability of a late delivery.

35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

So

P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235

What is the probability that a late package was delivered by express delivery service 2

P(B|A) = \frac{0.65*0.02}{0.0235} = 0.5532

55.32% probability that a late package was delivered by express delivery service 2

5 0
2 years ago
Help please!!!!!!!!!!!!
masha68 [24]
It should be 5>=




Your welcome


7 0
2 years ago
Kim is watching a satellite launch from an observation spot 6 miles away. Find the angle of elevation from Kim to the satellite,
Allisa [31]

Answer:

Angle of elevation from Kim to the satellite launch = 6.654°

Step-by-step explanation:

The distance from Kim to the satellite launch

= 6 miles

Height of the satellite launch

= 0.7 miles

Angle of elevation from Kim to the satellite launch = b

Tan b = height of satellite/distance from Kim

Tan b= 0.7/6

Tan b= 0.1166667

b = tan^-1 (0.1166667)

b= 6.654°

Angle of elevation from Kim to the satellite launch = 6.654°

4 0
3 years ago
Simplify the expression -2(p+4)^2-3+5p.What is the simplified expression in standard form?​
Leokris [45]

Answer: -2x²-11x-35

Step-by-step explanation:

-2(p+4)²-3+5p

-2(x²+8x+16)-3+5x

-2x²-11x-35

8 0
3 years ago
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