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Vanyuwa [196]
3 years ago
12

Can someone please help me on this question?

Mathematics
1 answer:
solniwko [45]3 years ago
4 0

ANSWER:

According to question, our g(x) becomes f(x) - 5.

When x = 1,

f(x) - 5 = 5 - 5 = 0.

When x = 2,

f(x) - 5 = 7 - 5 = 2.

When x = 3,

f(x) - 5 = 11 - 5 = 6.

When x = 4,

f(x) - 5 = 19 - 5 = 14.

So, <u>Correct choice</u> - [D]

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Is there anymore details to this?
5 0
3 years ago
What is the distance between point W and X to nearest hundredth?​
quester [9]

Answer:  16.97

<u>Step-by-step explanation:</u>

To find the distance from W to X, you can use the distance formula ...or... draw a right triangle using W and X as the vertices and use Pythagorean Theorem to find the hypotenuse. I will solve using the latter.

The y-distance from W to X is 12.

The x-distance from W to X is 12.

hypotenuse² = 12² + 12²

                      = 144 + 144

                      = 288

hypotenuse = \sqrt{288}

                     = 16.97

4 0
3 years ago
Simplify The Following: -4h + 22 + 6h -7
Vikentia [17]

Answer:

2h + 15

Step-by-step explanation:

-4h + 22 + 6h -7

2h + 22 - 7

2h + 15

3 0
3 years ago
Ariana bought 5 dozen pears at $36 per dozen . She discovered that 7 were rotten and she sold the rest at $4.50 each . Calculate
GrogVix [38]

Step-by-step explanation:

1 dozen = 12 pears

12 pears = $36

1 pear = 36/12 = $3

Total Cost of Pears = No. of pears x price of 1 pear

= (5x12) x 3

= 60 x 3

= $180

Sale of Pears = Price per pear x (Total Pears bought - Rotten Pears)

= $4.50 x (5x12-7)

= $4.50 x 53

= $238.50

Profit/Loss = Sale of Pears - Total Cost of Pears

= $238.50 - $180

= $58.50

Ariana made a profit of $58.50.

5 0
3 years ago
Read 2 more answers
find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest
Arlecino [84]

Answer:

Minimum 8 at x=0, Maximum value: 24 at x=4

Step-by-step explanation:

Retrieving data from the original question:

f(x)=x^{2}+8\:over\:[-1,4]

1) Calculating the first derivative

f'(x)=2x

2) Now, let's work to find the critical points

Set this

2x=0\\x=0    

0, belongs to the interval. Plug it in the original function

f(0)=(0)^2+8\\f(0)=8

3)  Making a table x, f(x) then compare

x|  f(x)

-1 | f(-1)=9  

0 | f(0)=8   Minimum

4 | f(4)=24 Maximum

4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.    

5 0
3 years ago
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