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Eddi Din [679]
3 years ago
15

Find five solutions for the linear equations 2x+y=5, and plot the solutions as points on a coordinate plane. Did i do this right

?

Mathematics
2 answers:
beks73 [17]3 years ago
7 0
For the second row i think it should be 2 + y = 5 because 2 x 1 equals 2
andreyandreev [35.5K]3 years ago
6 0
No it should be 2+y=5
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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
The private school enrollment of a city is 12.000. Enrollment is increasing at a rate of 4.5% annually. What would the
irakobra [83]

Answer:

28940.568

Step-by-step explanation:

3 0
2 years ago
Find the values of x and y.
hodyreva [135]

Answer:

C, (x = 100, y = 10)

Step-by-step explanation:

hi again,

(2x - 70) = (x + 30), by the Alternate Exterior Angles

x - 70 = 30

<em>x = 100</em>

<em />

(2x - 70) + 5y = 180, by the Linear Pair Theorem

2(100) - 70 + 5y = 180

200 - 70 + 5y = 180

130 + 5y = 180

5y = 50

<em>y = 10</em>

8 0
3 years ago
A ladder is placed against the side of a house. The top of the ladder is 12 feet above the ground. The base of the ladder is 5 f
Colt1911 [192]
This is the Pythagorean theorem where the 2 legs of a triangle squared add up to equal the squared hypotenuse (a^2 + b^2 = c^2)

The equation would be
12^2 + 5^2 = x^2

144 + 25 = 169

The square root of 169 = 13

Answer - 13 ft
3 0
3 years ago
Which angles are right? Check all that apply
Hitman42 [59]

Answer:

If I remember correctly, right angles are 90 degree angles. So the answers would be A. B. and C.

Step-by-step explanation:

If you see the little box on the angle, that means it's a 90 degree (right) angle.

5 0
3 years ago
Read 2 more answers
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