Answer:
t= 3.1 years
Step-by-step explanation:
A = A_0 e kt
Half life(1/2) = 26 yrs
1/2 = 1_0 e^k.26
ln(1/2) = ln(e^26k)
26k. ln(e) = ln(1/2)
k = 1/26* ln(1/2)
k = -0.0267
A = A_0 e^kt
0.92 = 1.e^(-0.0267)t
ln(0.92) = ln(e^(-0.0267)t
-0.0267t .ln(e) = ln(0.92)
t = ln(0.92) / -0.0267
t = 3.122
t = 3.1years (approximate to 1 d.p)
Answer:
y = -8
Step-by-step explanation:
6/-3 = -2
4 * -2 = -8
y = -8
So...notice first off, the 0.6 has 1 decimal, the 0.0024 has 4 decimals
what happens is, the dot goes poof BUT, you need to add as many zeros to each number as the other's decimals.
the 0.6 has one decimal, so 0.0024 gets an added zero and loses the dot, to become 000240.
the 0.0024 has four decimals, thus the 0.6 gets added 4 zeros then, and loses the dot, to become 060000
and then you divided that, those are the dividend and divisor.
<span>As restaurant owner
The probability of hiring Jun is 0.7 => p(J)
The probability of hiring Deron is 0.4 => p(D)
The probability of hiring at least one of you is 0.9 => p(J or D)
We have a probability equation:
p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D)
p(J and D) = 1.1 - 0.9 = 0.2
So the probability that both Jun and Deron get hired is 0.2.</span>
X^3= (125/27)
To find the answer, find the cube root of both sides
x= ∛(125/27)
∛(125/27)= (∛125)/(∛27) = 5/3
Final answer: 5/3