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melisa1 [442]
3 years ago
12

40 POINTS

Mathematics
2 answers:
scoray [572]3 years ago
5 0

Answer:

  • 4 red and 3 blue

Step-by-step explanation:

Let red candy weighs r and blue candy weighs b

<u>Total weight is 7 pounds:</u>

  • r + b = 7

<u>Red costs $1.5 per pound, blue costs $2 per pound and total cost is $12</u>

  • 1.5r + 2b = 12

We have two  equations.

<u>Solve by elimination, double the first equation and subtract the second equation from the first:</u>

  • 2r + 2b = 14
  • 1.5r + 2b = 12

<u>Subtract and solve for r:</u>

  • 2r - 1.5r = 14 - 12
  • 0.5r = 2
  • r = 4

<u>Find b using the first equation:</u>

  • b = 7 - r
  • b = 7 - 4 = 3

<u>The answer is:</u>

  • Mike had 4 pounds of red and 3 pounds of blue candies.
Evgesh-ka [11]3 years ago
4 0

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

Let the red candy be r and blue candies be b

r + b = 7(EQ 1)

1.5r + 2b = 12

2r + 2b = 14

Now,

(1.5r + 2b = 14) = (2r + 2b + 12)

2r - 1.5r = 14 - 12

0.5r = 2

r = 2/0.5

r = 4

Using equation 1

4 + b = 7

4b = 7

b = 7 - 4

b = 3

\\

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