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2 years ago

Which statement best describes g(x) = 3x + 6 - 8 and the parent function f(x) = } ?

Mathematics

1 answer:

kumpel [21]2 years ago

3 0

Answer:

In general gf(x) is not equal to fg(x)

Some pairs of functions cannot be composed. Some pairs of functions can be composed only for certain values of x.

Only with they can be composed some values of x are the ranges of g(x) and f(x) are the same, and their domains are also the same. Or else lies inside it.

Step-by-step explanation:

g(x) = 3x + 6 - 8, f(x) = √x.

The domain of a composed function is either the same as the domain of the first function, or else lies inside it

The range of a composed function is either the same as the range of the second function, or else lies inside it.

Or vice versa

Now only positive numbers, or zero, have real square roots. So g is defined only for numbers

greater than or equal to zero. Therefore g(f(x)) can have a value only if f(x) is greater than or

equal to zero. You can work out that

f(x) ≥ 0 only when x ≥3/2

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How many times dose 12 go into 41

jonny [76]

Answer:

3.42

Step-by-step explanation:

41/12 is 3.42

3 0

2 years ago

Read 2 more answers

Find the y and the x intercepts of the graph of the equation of y=3x+1

BaLLatris [955]

Answer:

x-intercept ⇨ -1/3

y-intercept ⇨ 1

Step-by-step explanation:

⟺ Finding the x-intercept, substitute y = 0

$y=3x+1\\0=3x+1\\3x+1=0\\$

Move 1 to subtract the another side.

$3x=-1$

Then move 3 to divide -1, leaving only x as a subject since we want to find the x-intercept.

$x=-\frac{1}{3}$ #

⟺ Finding the y-intercept, substitute x = 0

$y=3x+1\\y=3(0)+1\\y=0+1$

$y=1$ #

Tips:

Here's the tips about finding the intercepts of the graph.

⟺ For x-intercept, It's like solving an equation to find the x-term.

⟺ For y-intercept, It's like using the constant to answer.

As for y = mx+b where m = slope and b = y-intercept.

For a linear function, It's not necessary to substitute x = 0 just to find y-intercept as we can answer the constant as our y-intercept.

7 0

2 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

so the area is

$\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx$

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the $i$ -th subinterval are, respectively,

$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$