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3 years ago

Please help

Advanced Placement (AP)

1 answer:

Dafna1 [17]3 years ago

5 0

Hello. This question is incomplete. The full question is:

John had his annual physical with his physician and after receiving his blood work results, his doctor is concerned. John’s total cholesterol is 309. His HDL is 25 and his LDL is 220. His triglycerides are 320. John eats fast food every day, usually twice per day. His favorite restaurants are Kentucky Fried Chicken and McDonald’s.

Explain in detail why John’s doctor is concerned about his blood work. What are the risks of having high total cholesterol? LDL? Triglycerides?

Answer and Explanation:

John's doctor is concerned because he has high levels of cholesterol, LDL and triglycerides, which means that he has a high chance of suffering a heart attack or stroke.

High cholesterol levels can cause a heart attack or stroke in an individual like John. This is because cholesterol accumulates on the walls of the arteries and can completely block the blood flow.

High levels of LDL, likewise, cause heart attacks and strokes, but in addition, excess LDL can cause cardiovascular problems, weakening the heart intensely.

High levels of triglycerides can trigger inflammation in the pancreas, accumulation of fat in the liver, in addition to causing heart attacks and strokes due to clogged arteries.

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Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.

mafiozo [28]

Answer:

$r = 5.24$ --- Radius

$h = 10.48$ --- Height

Explanation:

Given

Object: Can (Cylinder)

$Surface\ Area = 517.8cm^2$

Required

Maximize the volume

The surface area is:

$S.A = 2\pi r^2 + 2\pi rh$

Substitute 517.8 for S.A

$517.8 = 2\pi r^2 + 2\pi rh$

Divide through by 2

$258.9 = \pi r^2 + \pi rh$

Factorize:

$258.9 = \pi r(r + h)$

Divide through by $\pi r$

$\frac{258.9}{\pi r} = r + h$

Make h the subject

$h = \frac{258.9}{\pi r} - r$ --- (1)

Volume (V) is calculated as:

$V = \pi r^2h$

Substitute (1) for h

$V = \pi r^2(\frac{258.9}{\pi r} - r)$

Open Bracket

$V = 258.9r - \pi r^3$

Differentiate V

$V' = 258.9 - 3\pi r^2$

Set V' to 0

$0 = 258.9 - 3\pi r^2$

Collect Like Terms

$3\pi r^2 = 258.9$

Divide through by 3

$\pi r^2 = 86.3$

Divide through by $\pi$

$r^2 = \frac{86.3}{\pi}$

$r^2 = \frac{86.3*7}{22}$

$r^2 = \frac{604.1}{22}$

Take square root of both sides

$r = \sqrt{\frac{604.1}{22}$

$r = 5.24$

Recall that:

$h = \frac{258.9}{\pi r} - r$

Substitute 5.24 for r

$h = \frac{258.9}{\pi * 5.24} - 5.24$

$h = \frac{258.9*7}{22 * 5.24} - 5.24$

$h = \frac{1812.3}{115.28} - 5.24$

$h = 15.72 - 5.24$

$h = 10.48$

Hence, the dimension that maximize the volume is:

$r = 5.24$ --- Radius

$h = 10.48$ --- Height

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lesya692 [45]

Answer:

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Answer:

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Explanation:

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Answer:

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Explanation:

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