Answer:
its either b or d
Step-by-step explanation:
4 x 7 divided by 9. Set 7 equal to 7/1. Now you have 4/9 x 7/1. Multiply numerators and denominators
Answer:
14
Step-by-step explanation:
Given the indicinal expression 64^5/6 + 27^2/3 - 81^3/4
According to indices;
![a^{m/n} = (\sqrt[n]{a}) ^m](https://tex.z-dn.net/?f=a%5E%7Bm%2Fn%7D%20%3D%20%28%5Csqrt%5Bn%5D%7Ba%7D%29%20%5Em)
Applying this to the question
![64^{5/6} \\= (\sqrt[6]{64}) ^5\\= 2^5= 32](https://tex.z-dn.net/?f=64%5E%7B5%2F6%7D%20%5C%5C%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%20%5E5%5C%5C%3D%202%5E5%3D%2032)
Similarly
![27^{2/3}\\= (\sqrt[3]{27}) ^2\\= 3^2\\= 9\\](https://tex.z-dn.net/?f=27%5E%7B2%2F3%7D%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B27%7D%29%20%5E2%5C%5C%3D%203%5E2%5C%5C%3D%209%5C%5C)
Also;
![81^{3/4}\\= (\sqrt[4]{81}) ^3\\= 3^3\\= 27](https://tex.z-dn.net/?f=81%5E%7B3%2F4%7D%5C%5C%3D%20%28%5Csqrt%5B4%5D%7B81%7D%29%20%5E3%5C%5C%3D%203%5E3%5C%5C%3D%2027)
Substitute inti the original equation
64^5/6 + 27^2/3 - 81^3/4
= 32 + 9- 27
= 41 - 27
= 14
Hence the required answer is 14
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 4500
A = 6300
r = 6.75% = 6.75/100 = 0.0675
n = 2 because it was compounded 2 times in a year.
Therefore,.
6300 = 4500(1 + 0.0675/2)^2t
6300/4500 = (1 + 0.03375)^2t
1.4 = 1.03375^2t
Taking log of both sides of the equation, it becomes
Log 1.4 = 2t log 1.03375
0.1461 = 2t × 0.0144 = 0.0288t
t = 0.1461/0.0288
t = 5.1 years.
Answer:
This is not possible.
Step-by-step explanation:
6 m = 600 cm
A triangle with a 600 cm leg and a 10 cm hypotenuse is impossible
If the 6 m should have been 6 cm, then:
Using the Pythagorean theorem:
base² = 10² - 6² = 100 - 36 = 64
base = √64 = 8
d² = 8² + 15² = 64 + 225 = 289
d = √289 = 17 cm , not meters
