184 x 7 = 1288
7 x 6 = 42
so you have 42 <span>defective bulbs</span>
Solve the following system using substitution:
{y + 2.3 = 0.45 x
{-2 y = -3.6
In the second equation, look to solve for y:
{y + 2.3 = 0.45 x
{-2 y = -3.6
-3.6 = -18/5:
-2 y = -18/5
Divide both sides by -2:
{y + 2.3 = 0.45 x
{y = 9/5
Substitute y = 9/5 into the first equation:
{4.1 = 0.45 x
{y = 9/5
In the first equation, look to solve for x:
{4.1 = 0.45 x
{y = 9/5
4.1 = 41/10 and 0.45 x = (9 x)/20:
41/10 = (9 x)/20
41/10 = (9 x)/20 is equivalent to (9 x)/20 = 41/10:
{(9 x)/20 = 41/10
{y = 9/5
Multiply both sides by 20/9:
Answer: {x = 82/9
{y = 9/5
4(x-3)-2+2x=5(3x-7)-9x
4x-12-r+2x=5(3x-7)-9
4x-12-r+2x=15x-35-9x
6x-12-r=15x-35-9x
6x-12-r=6x-35
add 12 to -35 which equals -23.
add 6x+6x it cancels out to 0.
-r=-23
to make r positive just add it -23
since 23 is already negative it would become a positive because a negative + negative= positive
answer: r=23
<span>6+5w-9f-3
Substitute the variables for numbers
6+5(3)-9(4)-3
Multiply 5 by 3 and -9 by 4
6+15-36-3
Combine like terms
Final Answer: -18
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