See the attached picture for the calculation:
Answer:
10.5%
Step-by-step explanation:
The tangent of the angle is the ratio of rise to run.
tan(angle) = grade
tan(6°) ≈ 0.105 = 10.5%
The grade will be 10.5% for an angle of elevation of 6°.
Answer:
14.3 km
Step-by-step explanation:
Using the paths shown, we would need to add the path length from Belmont to Yardley and Yardley to Oxford. When we add 8.5 and 5.8, we get 14.3 km.
Hence,
the distance from Belmont to Oxford is 14.3 km.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
I believe the answer to your question is going to be
D) g(x)=(x+3)^2
Hope I’m correct!
If you would like to simplify 21/78, you can do this using the following step:
21/78 = 7/26
<span><span>The result is </span>7/26 <span>(this is not a mixed number, because mixed
numbers can be made from numbers greater than 1 and 7/26 is less than 1).</span></span>
