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3 years ago

13

a tray is fill with several 500g bags of apples. the tray holds 8 kg in total. 5 bags of apples are sold .how many is left on th

e tray

1 answer:

kobusy [5.1K]3 years ago

5 0

8kg=8000g

8000/500=16
16-2=14

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What is f(4y)?? with f(x)=-2x-3

Olin [163]

Good evening ,

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Answer:

f(4y) = -8y - 3.

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Step-by-step explanation:

f(x) = -2x-3 Then f(4y) = -2(4y) -3 = -8y - 3.

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3 years ago

Which Equation could be used to find m, the number of miles he drove on his last trip?

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Answer:

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2 years ago

Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.

likoan [24]

Let $v$ be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

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where $s_A,\ s_B$ are the positions of trains A and B respectively, and t is the time in hours.

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2 years ago

Malcolm buys a 5/6 pound bag of black beans and a 3/4 pound bag of pinto beans how many pounds of beans does Malcolm have in all

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values

Slav-nsk [51]

Answer:

Systolic on right

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

$CV= \frac{\sigma}{\mu}$

And the best estimator is $\hat {CV} =\frac{s}{\bar x}$

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

$s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}$

For this case we have the following values:

$\bar x = 127.5, s= 18.68$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

For this case we have the following values:

$\bar x = 74.2 s= 12.65$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

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2 years ago