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3 years ago

12

Algebra 1

1 answer:

sammy [17]3 years ago

6 0

3x+y=15
17x+y=20
x=4
y6

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Dylan estimates the first digit in the quotient. (46/3,662 estimate is 6) Is Dylan's estimate too high or too low?

Mumz [18]

I'm gonna say he's to high.

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3 years ago

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What is log(z^4/5) written in expanded form?

Ostrovityanka [42]

To get answer:

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(\frac{a}{b}\right)=\log _c\left(a\right)-\log _c\left(b\right)\\\log _{10}\left(\frac{z^4}{5}\right)=\log _{10}\left(z^4\right)-\log _{10}\left(5\right)\\=\log _{10}\left(z^4\right)-\log _{10}\left(5\right)\\\mathrm{Simplify}\:\log _{10}\left(z^4\right)\\\log _{10}\left(z^4\right)\\\mathrm{Apply\:log\:rule\:}\log _a\left(x^b\right)=b\cdot \log _a\left(x\right),\:\quad \mathrm{\:assuming\:}x\:\ge \:0\\=4\log _{10}\left(z\right)\\$

Answer: $4\log _{10}\left(z\right)-\log _{10}\left(5\right)$

Answer: 4logz−log5

4 0

4 years ago

3–34 The average atmospheric pressure in Denver (elevation = 1610 m) is 83.4 kPa. Determine the temperature at which water in an

SOVA2 [1]

Answer:

T = 94.59 degree C

Step-by-step explanation:

Given data:

P= 83.4 kPa

$P= 83.4 \times 10^3 Pa \frac{1 bar}{10^5 Pa}$

P = 0.834 bar

for Saturated table

P = 0.8 bar T = 93.50 degree C

P = 0.9 bar T = 96.71 degree C

from interpolation method

$\frac{0.834 - 0.8}{0.9 - 0.8} = \frac{z}{96.71 - 93.5}$

z = 1.0914

T = 93.5 + z = 94.59 degree C

6 0

4 years ago

Please help with multiple choice question

Volgvan

Answer:

D: {9, 21, 33}

Step-by-step explanation:

Ken worked 2, 8 and 14 hours on 3 separate days.

For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;

For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and

For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33

Thus, the range of this function for the days given is {9, 21, 33} (Answer D)

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3 years ago

Someone please help

hram777 [196]

Answer:

What's the question?

Step-by-step explanation:

4 0

3 years ago

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