Answer:
C
Step-by-step explanation:
Therefore, the correct answer is choice C. Hope this helps!
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Bill's speed is constant after 5 seconds and 45 meters into the race.
Correct responses:
a. Bill's maximum speed is 8 m/s
b. 24 meters
c. 57 meters
<h3>Methods used to calculate speed and distance traveled</h3>Given parameters are;
The distance of the race = 100 meter
Distance at which Bill reaches maximum speed = 45 meters
Speed Bill maintains after 5 seconds = The maximum speed
Time at which Bill is 85 meters from the starting line = 10 seconds after start
a. Required;
Bill's maximum speed in meters.
Solution:
Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m
Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s
Therefore;
b. i. Required:
The distance Bill will run for 3 seconds at the maximum speed;
Solution:
Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>
<em />
The distance traveled at maximum speed in 3 seconds is therefore;
Distance = 8 m/s × 3 s = 24 m
The distance Bill travels in 3 seconds at the maximum speed is 24 meters.
ii) The distance Bill travels at 8 seconds after start, is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 3 seconds = 24 meters
Therefore;
- Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>
c. Bill's distance 6.5 seconds after the start of the race is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters
- Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>
Learn more about distance, speed, time, relationship here:
https://brainly.in/question/49075584
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.
The standard deviation is a measure of dispersion obatined from the sample variance and is given by:
Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.