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2 years ago

I NEED HELP ASAP PLEASEEEE

Mathematics

1 answer:

aleksandrvk [35]2 years ago

4 0

Answer: C. 512

Step-by-step explanation:

V= s^3

V= 8 x 8 x 8 = 512 cubic inches

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What is the value of z?

Shalnov [3]

Answer:

3 (z = 35)

Step-by-step explanation:

(22 + 19) + 104 + z = 180° => triangle sum theorem

41 + 104 + z = 180

145 + z = 180

145 + z - 145 = 180 - 145

z = 35

8 0

3 years ago

Will give brainliest, can somebody help me with this question

Andrew [12]

Answer:

A = 5x + 5

Step-by-step explanation:

Area of Parallelogram Formula: A = bh

Since we are given <em>b</em> = 5 and <em>h</em> = x + 1, simply plug it into the formula:

A = 5(x + 1)

A = 5x + 5

4 0

3 years ago

Read 2 more answers

The national weather service keeps records of rainfall in valleys. Records indicate that in a certain valley the annual rainfall

Setler79 [48]

Answer:

The mean is 95 and the standard deviation is 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Population:

Mean 95, Standard deviation 12

Samples of size 36:

By the Central Limit Theorem,

Mean 95

Standard deviation $s = \frac{12}{\sqrt{36}} = 2$

4 0

2 years ago

D3a2−(c+b) if a=−2, b=3, c=−12, and d=−4

UkoKoshka [18]

Answer:

Step-by-step explanation:

(-12)(3)(-2)(2)-(-12+3)

8 0

3 years ago

Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.

kolezko [41]

Answer:

$A=4.5u^2$

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

$y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3$

$y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9$

The integral will be the subtraction of the curve $y=3x$ and $y=x^2$ (In the graph you can see y=3x is the upper curve):

$\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2$

6 0

2 years ago