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asambeis [7]
2 years ago
13

Can u help me with my workk

Mathematics
1 answer:
eimsori [14]2 years ago
6 0
You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)
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Pie
The answer is 60% but you can make it higher if your teacher let's you correct it.
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2 years ago
Prove A-(BnC) = (A-B)U(A-C), explain with an example​
NikAS [45]

Answer:

Prove set equality by showing that for any element x, x \in (A \backslash (B \cap C)) if and only if x \in ((A \backslash B) \cup (A \backslash C)).

Example:

A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace.

B = \lbrace0,\, 1 \rbrace.

C = \lbrace0,\, 2 \rbrace.

\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}.

\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}.

Step-by-step explanation:

Proof for [x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))] for any element x:

Assume that x \in (A \backslash (B \cap C)). Thus, x \in A and x \not \in (B \cap C).

Since x \not \in (B \cap C), either x \not \in B or x \not \in C (or both.)

  • If x \not \in B, then combined with x \in A, x \in (A \backslash B).
  • Similarly, if x \not \in C, then combined with x \in A, x \in (A \backslash C).

Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) as required.

Proof for [x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]:

Assume that x \in ((A \backslash B) \cup (A \backslash C)). Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

  • If x \in (A \backslash B), then x \in A and x \not \in B. Notice that (x \not \in B) \implies (x \not \in (B \cap C)) since the contrapositive of that statement, (x \in (B \cap C)) \implies (x \in B), is true. Therefore, x \not \in (B \cap C) and thus x \in A \backslash (B \cap C).
  • Otherwise, if x \in A \backslash C, then x \in A and x \not \in C. Similarly, x \not \in C \! implies x \not \in (B \cap C). Therefore, x \in A \backslash (B \cap C).

Either way, x \in A \backslash (B \cap C).

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) implies x \in A \backslash (B \cap C), as required.

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Determine the slope of the line with the following graph
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Find the slope from a graph

Locate two points on the line whose coordinates are integers.

Starting with the point on the left, sketch a right triangle, going from the first point to the second point.

Count the rise and the run on the legs of the triangle.

Take the ratio of rise to run to find the slope. m=riserun.

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Will mark brainlest helpppp pleaseeeee​
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Answer:

come to mya massanger dk khanal fb user

Step-by-step explanation:

i will teach you by sending picture

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The difference between a number and 7 is greater than -23
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-23 is a negative number so that means 7 is a greater number. any number with a minus sign like this - means it’s a negative number, so any number that you have to compare it to and if that number has nothing before or after it, then that would be the greater number
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