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mote1985 [20]
3 years ago
13

Match each set of numbers with their least common multiple.

Mathematics
1 answer:
mylen [45]3 years ago
5 0

Answer:

27, 12, and 36  = 108

22 and 4  = 44

14 and 12  = 84

25 and 8  =200

9, 8, and 7  = 504

32, 24, and 18  = 288

Step-by-step explanation: You are welcome.

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Helpppppppppppppp helpppppppppppppp​
jarptica [38.1K]

Answer:

A.

1. 6/9

2. 6/3

3. 3/6

4. 9/6

5. 3/9

B.

1. 8/12

2. 3/7

3. 5/3

4. 12/15

5. 20/25

Step-by-step explanation:

You can turn a ratio from #:# into #/# so if the ratio was 3:9 the fraction form would be 3/9.

4 0
3 years ago
Someone please help me PLEASE. <br> With explanations.
Nadusha1986 [10]

Answer:

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navneet175285

Step-by-step explanation:

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3 0
3 years ago
HELP HELP HELP HELP HELP HELL
vitfil [10]

Answer:

it sould be D because rise over run.

Step-by-step explanation:

at the point its 5/6 and the only answer with that fraction is D. or it depends because if you're looking for the begening of the dotted lines then it's C .but if you're looking for end point then it's D. if you don't know ask me and ill see what i can do

3 0
3 years ago
cynthia invests some money in a bank which pays 5% compound interest per year. She wants it to be worth over £8000 at the end of
exis [7]

Answer:

The smallest amount is \£6,911

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3\ years\\ A=\£8,000\\ r=5\%=5/100=0.05\\n=1  

substitute in the formula above

8,000=P(1+\frac{0.05}{1})^{1*3}  

solve for P

8,000=P(1.05)^{3}  

P=8,000/(1.05)^{3}  

P=\£6,910.70  

Round to the nearest pound she can invest

The smallest amount is \£6,911

6 0
3 years ago
In order to circumscribe a circle on a triangle, which line must you construct?
SIZIF [17.4K]
<span>D) perpendicular bisector <em>I believe.
</em></span>
6 0
3 years ago
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