Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
24)
The number 1/10 can be expressed as a decimal by dividing the top number by the bottom.
1/10=0.1
0.8>0.1
0.8>1/10
26)
The number 3/5 can also be expressed as a decimal, using the method I described for 24.
3/5=0.6
0.6>0.35
3/5>0.35
28)
The number 2/5 can also be expressed as a decimal.
2/5=0.4
0.4>0.3
2/5>0.3
30)
The number 1/6 cannot be expressed as a decimal. So, express 0.2 as a fraction.
0.2=2/10=1/5
1/5=6/30
1/6=5/30
6/30>5/30
0.2>1/6
Hope this helps!
It seemed like it should have been so simple. There was nothing inherently difficult with getting the project done. It was simple and straightforward enough that even a child should have been able to complete it on time, but that wasn't the case. The deadline had arrived and the project remained unfinished.
Answer:
I'm 99% sure the answer is A
Step-by-step explanation:
