Quadratic Equations in Single Variable
n²-3n+10=0
2x²+2x+1=0
25b²-16=0
f²-3f+2=0
1/3m +2m=4
a²=225
Linear Equation in single Variable
8-3k=12
5w+5=0
10u-5=8
Linear Equation in Two Variable
2y-z=9
3r+2e=6
d=3e-7
<h3>What is an equation?</h3>
It should be noted that an equation simply means the expression that's used to show the relationship between the variables.
In this case, the equation has been grouped.
Learn more about equations on:
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Group the given equations into two based on observed common properties.
Equations
n²-3n+10=0
8-3k=12
2y-z=9
2x²+2x+1=0
25b²-16=0
3r+2e=6
5w+5=0
f²-3f+2=0
d=3e-7
1/3m +2m=4
10u-5=8
a²=225
Hi there!
The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. Using this formula, we can plug in the given values and solve for the lateral area.
WORK:
LA = 2pi x r x h
LA = 2pi x 4.5 x 17
LA = 153pi mm^2
The correct answer is the first option - 153pi mm^2
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
The volume of the candle initially is:
V=Ab*h
Area of the base of the cylinder: Ab=pi*r^2
pi=3.14
Radius of the base: r=4 cm
Height of the cylinder: h=6 cm
Ab=pi*r^2
Ab=3.14*(4 cm)^2
Ab=3.14*(16 cm^2)
Ab=50.24 cm^2
V=Ab*h
V=(50.24 cm^2)*(6 cm)
V=301.44 cm^3
The candle melts at a constant rate of:
r=(60 cm^3)/(2 hours)=(120 cm^3)/(4 hours)=(180 cm^3)/(6 hours)
r=30 cm^3/hour
The amount of candle melted off after 7 hours is:
A=(30 cm^3/hour)*(7 hours)
A=210 cm^3
The percent of candle that is melted off after 7 hours is:
P=(A/V)*100%
P=[(210 cm^3)/(301.44 cm^3)]*100%
P=(0.696656051)*100%
P=69.66560510%
Rounded to the nearest percent
P=70%
Answer: 70%
ITS MUltipling by 3 silly its 243
Answer:
38.3
Step-by-step explanation:
hope I helped
