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According to Vieta's Formulas, if
![x_1,x_2](https://tex.z-dn.net/?f=x_1%2Cx_2)
are solutions of a given quadratic equation:
Then:![a(x-x_1)(x-x_2)](https://tex.z-dn.net/?f=a%28x-x_1%29%28x-x_2%29)
is the completely factored form of
![ax^2+bx+c](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc)
.
If choose
![x=d^2](https://tex.z-dn.net/?f=x%3Dd%5E2)
, then:
![\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E2-8x%2B16%3D0%5C%5C%5C%5Cx_%7B1%2C2%7D%3D%20%5Cfrac%7B8%5Cpm%20%20%5Csqrt%7B64-64%7D%20%7D%7B2%7D%3D4%20)
So, according to Vieta's formula, we can get:
![x^2-8x+16=(x-4)(x-4)= (x-4)^2](https://tex.z-dn.net/?f=x%5E2-8x%2B16%3D%28x-4%29%28x-4%29%3D%20%28x-4%29%5E2)
But
![x=d^2](https://tex.z-dn.net/?f=x%3Dd%5E2)
:
Answer:
a)yes
Step-by-step explanation:
5 times 5 is 25
8 times 5 is 40
4,646,536 is the right answer
The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.
<h3>How to determine the density curves?</h3>
In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:
Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1
Area A = 10 × 0.1
Area A = 1 sq. units (True).
For curve B, we have:
Area B = (3 × 3) × 0.1
Area B = 9 × 0.1
Area B = 0.9 sq. units (False).
For curve C, we have:
Area C = (3 × 4 - 2 × 1) × 0.1
Area C = 10 × 0.1
Area C = 1 sq. units (False).
For curve D, we have:
Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1
Area D = 10 × 0.1
Area D = 1 sq. units (True).
For curve E, we have:
Area E = (1/2 × 4 × 5) × 0.1
Area E = 10 × 0.1
Area E = 1 sq. units (True).
Read more on density curves here: brainly.com/question/26559908
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