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3 years ago

A = 4 6 9 which is the correct answer?

Mathematics

1 answer:

Studentka2010 [4]3 years ago

4 0

Answer:

Step-by-step explanation:

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Why you find 39 when you estimate difference 206and 167<br> Thinks

Mama L [17]

You get 39 as an answer because you're taking 209 minus 167 and 39 is the answer that you get.

7 0

3 years ago

Identify the 12th term of the arithmetic sequence in which a7 = 40 and a18 = 106.

Lady_Fox [76]

we are given

airthematic sequence

we can use nth term formula

$a_n=a_1+(n-1)d$

n is number of terms

an is nth term

d is common difference

a1 is first term

We are given

a7=40

we can use it

$a_7=a_1+(7-1)d$

$40=a_1+6d$

$a_1+6d=40$

a18 = 106

$a_1_8=a_1+(18-1)d$

$a_1+17d=106$

we can subtract both equations

$a_1+17d-a_1-6d=106-40$

$11d=66$

$d=6$

now, we can find a1

$a_1+6d=40$

we can plug d=6

$a_1+6*6=40$

$a_1=4$

12th term:

$a_1_2=a_1+(12-1)d$

now, we can plug values

$a_1_2=4+(12-1)*6$

$a_1_2=4+66$

$a_1_2=70$

so, 12th term is 70...........Answer

3 0

3 years ago

Los números 4,3×-3,4× esta en progesion aritmética cuál es el cuarto termino

77julia77 [94]

Answer: Le preguntaste a tu maestro?

Step-by-step explanation:

5 0

3 years ago

The variables a, b, and c represent polynomials where a = x 1, b = x2 2x − 1, and c = 2x. what is ab c in simplest form?

inna [77]

If you would like to write a * b + c in simplest form, you can do this using the following steps:

a = x + 1
b = x^2 + 2x - 1
c = 2x
a * b + c = (x + 1) * (x^2 + 2x - 1) + 2x = x^3 + 2x^2 - x + x^2 + 2x - 1 + 2x = x^3 + 3x^2 + 3x - 1

The correct result would be x^3 + 3x^2 + 3x - 1.

7 0

3 years ago

Read 2 more answers

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$

Use $\cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1$

$\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}$

7 0

2 years ago