Answer:
Step 2
Step-by-step explanation:
Meredith made a fatal mistake or error in step 2;
Any quadratic problem will always have two solutions. Therefore since, we only have one solution here, it is wrong. The mistake was incurred in step 2;
From the given problem ;
<u> Wrong right</u>
2(x + 4)² = 242
(x + 4)² = 121 Step 1
x+4=11 Step 2 x + 4 = ± 11
x = 7 Step 3 x + 4 = 11 or x + 4 = -11
x = 11- 4 or x = -11 - 4
x = 7 or -15
Answer:
Boundedness requires that there is only a bounded number of different kinds of parts
Step-by-step explanation:
Answer
its 500 and 8
Step-by-step explanation:
got it from khan academy
Answer:
Step-by-step explanation:
the question is asking for the length of the side labeled x
use Pythagoras' theorem to find that side
where c = x because c represents the hypotenuse in the theorem and x is on the hypotenuse in this problem
c = 
sooo plug in a = 14 and b = 10
c = 
c = 
c = 
c= 17.20465..... ( that's the approx. length of side x in the problem )
since this is a right triangle we could use trigonometry to find the two angles use SOH CAH TOA to remember how those functions fit on the triangle.
Sin(Ф)=Opp/Hyp Cos(Ф)=Adj/Hyp Tan(Ф)=Opp/Adj
since we know the Hyp (hypotenuse) and the side adjacent will be the side with the 10 soooo...
Cos(Ф)=10/17.20465
Ф = arcCos(10/17.20465)
Ф = 54.4623° is the angle on the side with 10
the side with 14 then has an angle of 35.5376°
:)
Green paint is made by mixing yellow and blue paint. Given that, every 4 gallons of green paint contains 3 gallons of blue paint, how many gallons of yellow paint is in 4 gallons of green paint? Green-blue=yellow
4-3=1 Therefore 1 gallon of yellow paint is in 4 gallons of paint.
The ratio of blue to yellow is 3:1
If there are 16 gallons of green paint, how many gallons blue and yellow are in it? blue= 3 in 4 green
If 16=4
=3
3/4*16=12 Therefore there are 12 gallons of blue paint in 16 gallons of green paint.
Yellow=1 in 4 gallons
If16=4
=1
1/4*16=4 Therefore there are 4 gallons of yellow paint in 16 gallons of green paint.
I am not so sure about this but I hope it helps.Sorry if it doesn't