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3 years ago

Create a pattern with the rule. -4.

1 answer:

7 0

One pattern is 22, 18, 14, 10, 6, 2 hope this helps just keep subtracting 4. You can go from the highest number to the lowest. Thanks for asking!

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3. Describe the solution to the equation.

Law Incorporation [45]

I don’t really know? What grade is this?

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3 years ago

at the start of a road trip a car had 20 gallons of gas in the tank. during the trip the care consumed 4 1/8 gallons. how much g

Pie

15 7/8 gallons. 20-4 1/8 = 15 7/8.

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3 years ago

Alton has been recording the number of apples on his apple tree each week:

Alex_Xolod [135]

1 represent the number of apples at the start.

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3 years ago

Read 2 more answers

The parallelogram has an area of 20 square inches. What are the dimensions of the parallelogram, to the nearest hundredth of an

Alik [6]

Answer:

Step-by-step explanation:

Since x is along the entire parallelogram we will use cosine to figure out it's length.

First we do cos(40) and get cos(40)=.7660

This .7660 is equal to $\frac{Adjacent}{Hypotenuse}$ or $\frac{x}{4}$

So we do .7660*4 and get 3.064 in for x

A is the only option with x=3.06 so it is the correct answer

8 0

3 years ago

Not sure how I am supposed to arrive to an answer

ANEK [815]

Integrating both sides once gives

$\dfrac{\mathrm d\mathbf r}{\mathrm dt}=2e^t\,\mathbf i+3e^{-t}\,\mathbf j+4e^{2t}\,\mathbf k+\mathbf c$

where $\mathbf c$ is an arbitrary constant vector. Use the initial condition to find its value:

$\dfrac{\mathrm d\mathbf r}{\mathrm dt}(0)=-\mathbf i+7\,\mathbf j=(2+c_1)\,\mathbf i+(3+c_2)\,\mathbf j+(4+c_3)\,\mathbf k$

$\implies\mathbf c_1=-3\,\mathbf i+4\,\mathbf j-4\,\mathbf k$

Integrate again:

$\mathbf r(t)=2e^t\,\mathbf i-3e^{-t}\,\mathbf j+2e^{2t}\,\mathbf k+\mathbf c_1t+\mathbf c_2$

where $\mathbf c_2$ is another arbitrary vector of constants. Use the other initial condition to determine its components:

$\mathbf r(0)=6\,\mathbf i+\mathbf j+3\,\mathbf k=(2+c_1)\,\mathbf i+(-3+c_2)\,\mathbf j+(2+c_3)\,\mathbf k$

$\implies\mathbf c_2=4\,\mathbf i+4\,\mathbf j+\mathbf k$

Then the particular solution to this ODE is

$\boxed{\mathbf r(t)=(2e^t-3t+4)\,\mathbf i+(-3e^{-t}+4t+4)\,\mathbf j+(2e^{2t}-4t+1)\,\mathbf k}$

5 0

4 years ago