Assuming your f(x) = x^3 +6x^2 +x^(1/2) and g(x) = x^(1/2), you have
.. f(x)/g(x) = x^(5/2) +6x^(3/2) +1
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If an exponent has any arithmetic in it, parentheses are needed around it.
Answer:
122 Degrees
Step-by-step explanation:
Since we are given that angle 1 and 2 make a linear pair:
angle 1 + angle 2 = 180 degrees ----------------------------(1)
We have also been told that angle 2 is 6 more than twice the measure of angle 1
Which means: angle 2 = (2*angle1) + 6 -------------------(2)
From putting the value of angle 2 in (1) from (2)
<em>angle 1 + 2*angle 1 + 6 = 180</em>
<em>3*angle 1 = 174</em>
angle 1 = 58 degrees -----------------------(3)
From (1) and (3):
<em>angle 2 + 58 = 180</em>
angle 2 = 122 degrees
Therefore, the measure of angle 2 is 122 degrees
Hello LovingAngel!
To find the slope, you can use the formulas

as well as

. I am using the latter to calculate and ensuring my answer with the former.
[Note: (x,y) is the format for ordered pairs]
First pair: value 1:(1,5) and value 2:(2,8)

->

->

or 3.
The slope for (1,5) and (2,8) is 3(/1). Second pair: value 1: (3,1) value 2 (3,-1)

->

->
Slope for the second pair is -2/0Checking work with

1. Slope: 3/1, meaning rise (y) +3 and run (x) +1. (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>
answer
10
step-by-step explanation
the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7
substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)
sin(x) = cos(y)
sin(2k + 3) = cos(6k + 7)
we know that sin(x) = cos(90 -x)
sin(2k + 3)
= cos(90 - (2k + 3) )
= cos(90 - 2k - 3)
= cos(87 - 2k)
substitute this into the equation sin(2k + 3) = cos(6k + 7)
sin(2k + 3) = cos(6k + 7)
cos(87 - 2k) = cos(6k + 7)
87 - 2k = 6k +7
80 = 8k
k = 10