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2 years ago

What shape can be created by the given net? triangular pyramid wedge triangular prism cone

Mathematics

2 answers:

Juliette [100K]2 years ago

6 0

Answer:

triangular prism

Step-by-step explanation:

m_a_m_a [10]2 years ago

5 0

Answer:

your awnser would be option A. triangular prism

Step-by-step explanation:

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Which value is equivalent to sin20°?

AveGali [126]

Answer:

Option C. cos70°

Step-by-step explanation:

we know that

If two angles are complementary, then the sine of one angle is equal to the cosine of the other angle and the cosine of one angle is equal to the sine of the other angle

Remember that

Tow angles are complementary , if the sum of their angles is equal to 90 degrees

If A+B=90°

then

sin(A)=cos(B)

cos(A)=sin(B)

In this problem we have

A=20°

B=90°-20°=70°

therefore

sin(20°)=cos(70°)

cos(20°)=sin(70°)

6 0

3 years ago

PLEASE HELP! BRAINIEST WILL BE MARK IF RIGHT!

DerKrebs [107]

Answer:

X int : 5

Y int : 15

Step-by-step explanation:

y=15

3x=15

3/3 15/3

x=5

8 0

2 years ago

Read 2 more answers

What else would need to be congruent to show that triangle EFG=~ triangle HIJ by SSS?

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

In order to prove congruency using SSS, we need to prove that all three pairs of sides are congruent.

We are already given that EF ≅ HI and that FG ≅ IJ.

Therefore, the last bit of information we need to prove congruency using SSS is that EG ≅ HJ.

Hence, our answer is C.

8 0

2 years ago

An equation is shown below.<br> 3.5p = 28

grin007 [14]

Answer:

ncbdnifvdvdsovsv

Step-by-step explanation:

4 0

2 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago