78.5 inches, the area equation for a circle is pi times radius squared so to find it you would take 3.14*5^2 (radius is half the diameter) so it would be 3.14*25 which equals 78.5
Answer:
Step-by-step explanation:
The solution of a system of linear equations is the point of intersection of their graphs because the intersection represents the only x or y values that will satisfy both/all equations. The graph visually shows that the intersection of these equations is the only spot on the graph that all of the equations have in common. This means that only this spot will satisfy all equations. For example, the intersection may be (0,1); this means that for all equations an x value of 0 will always result in the y value of 1. However, an x or y value that satisfies one equation may not satisfy the others if they do not lead to the desired outcome.
Answer:9.13
Step-by-step explanation:There are three lines from the center to the sides. So they are all the same. you can see that the radius is 8 from one of the sides. You can find the area of the big triangle by knowing that 2 of the sides are 8 and 360-270=90 and that is a right triangle so we can use the pythagorean theorem to find the hypotenuse. 8^2+8^2=√128. And we can find the area by doing (8^2+8^2)/2=32 so each triangle is 16 units^2. To find out the lengths of the left triangle we have (.5*√128)^2=√32. So 8^2-32=x² x=√32. if the radius is 8 and the one side of the radius is √32 it would be 8-√32. and the other line touching the shaded area it √128 so we can say that the area of the non-little circle is the area of the whole circle-the almost circle. The area of the whole circle it 8^2*pi≈201.06. The area of the almost circle is 201.06*.75=150.79 because 270/360=.75 plus the area of the triangle (32) so the area is 182.79. So the area of the little thing is 201.06-182.79=18.27 divided by 2 =9.13
Answer:
∠HGJ and ∠KJL
Step-by-step explanation:
Corresponding angles are on the same side of the transversal where it cuts the two parallel lines, they have the same measure.
Answer:
3) Connect the adjacent points on circle A with line segments.
Step-by-step explanation:
An inscribed hexagon is a regular hexagon (a six-sided figure in which all of its angles are congruent and all of its sides are congruent) which is "inside" a circle (in this case, circle A). In the figure attached, an example is shown.
