3 years ago

HELP !!!!!!!!!!!!!! PLS

Mathematics

1 answer:

ANEK [815]3 years ago

4 0

Answer:

I think it will be (x+7)^2 =16

I'm not for sure but I think this is it.

Step-by-step explanation:

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Precalculus PLEASE HELP ME right answers only check all please

Alex_Xolod [135]

Given :

$cos(x)cos(\frac{\pi }{7}) + sin(x)sin(\frac{\pi }{7})=-\frac{\sqrt{2}}{2}$

We know the identity

$cos(x)cos(y) + sin(x)sin(y)=cos(x-y)$

We use this property to simplify the left hand side

So $cos(x)cos(\frac{\pi }{7}) + sin(x)sin(\frac{\pi }{7})=cos(x - \frac{\pi }{7})$

$cos(x - \frac{\pi }{7}) =-\frac{\sqrt{2}}{2})$

we know ,

when $cos(x) =-\frac{\sqrt{2}}{2})$ then

$x = \frac{3\pi }{4} , \frac{5\pi }{4}$

For $cos(x - \frac{\pi }{7}) =-\frac{\sqrt{2}}{2})$

$x - \frac{\pi }{7}= \frac{3\pi }{4} and x - \frac{\pi }{7}= \frac{5\pi }{4}$

Add $\frac{\pi }{7}$ on both sides

$x= \frac{3\pi }{4} + \frac{\pi }{7} and x= \frac{5\pi }{4} +\frac{\pi }{7}$

Finally we add 2npi for general solution

So options C and D are correct

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3 years ago