The rule to remember about generating the perpendicular family to a line is we swap the coefficients on and x and y, remembering to negate one of them. Then the constant is set directly from the intersecting point.
So we have
y = 3x + 2
-3x + 1y = 2
Swapping and negating gets the perpendiculars; the constant is as yet undetermined.
1x + 3y = constant
Since we want to go through (0,2), we could have just written
x + 3y = 0 + 3(2) = 6
3y = -x + 6
y = (-1/3) x + 2
Third choice
<h2>Question :</h2>
<em>Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)</em>
<h2>Answer :</h2>
<em>y = -3/2x - 4 </em>
<h2>Explanation :</h2>
y = mx + c
*m = gradien
•>looking for gradients
y=2/3x+9
m1 = 2/3
m2 = -3/2
•>line equation (-6,5)
y - y1 = m(x - x1)
y - 5 = -3/2(x - (-6))
y - 5 = -3/2(x + 6)
y - 5 = -3/2 - 9
y = -3/2x - 9 + 5
y = -3/2x - 4
That is impossible but I did some math so there are 2 ways that will equal more than 40.
6.7×6.0=40.2
6.5×6.2=40.3
Hope this helps!
0.44
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Answer:
(x + 2)(x - 5)
Step-by-step explanation:
Here are the steps:
