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GaryK [48]
2 years ago
9

Help me !!!! Pleaseee!!

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
5 0

Answer:

280000 - $56,000 down - $224,000 mortgage

245500 - $36,825 down - $208,675 mortgage

147200 - $139,850 down - $139,850 mortgage

110000 - $33,000 down - $77,000 mortgage

168000 - $16,800 down - $151,200 mortgage

Step-by-step explanation:

hram777 [196]2 years ago
4 0

Answer:

nani...

Step-by-step explanation:

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5x+9y-7x+2-5y-7x+2-3x
=(5-7-7-3)x+(9-5)y+2+2
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How many ways can the words in d-r-a-g-o-n-f-l-y be arranged
GarryVolchara [31]

Answer:

362880 ways

Step-by-step explanation:

The word dragonfly has 9 different letters.

So, to find how many ways this word can be arranged, we just need to calculate the factorial of 9:

First letter has 9 possibilities

Second letter has 8 possibilities (one used)

Third letter has 7 possibilities (two used), and so on.

So the number of ways is:

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X+y=-2 7x-4y=8 graph
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3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

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