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3 years ago

Simplify the Expression

Mathematics

1 answer:

White raven [17]3 years ago

5 0

(x^9/5 × x^2/5) / x^1/5 = x^11/5 / x^1/5 = x^(11/5-1/5) = x^10/5 = x^2 (ans)

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Reflection of a figure is called the post image true or false

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Answer:

True

Step-by-step explanation:

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4 years ago

What is the equation of the inverse of the function?<br><br><br> f(x)=x^4+16, x ≥ 0

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https://tex.z-dn.net/?f=q%3D0%2C%5C%20r%3D2%2C%5C%20s%3D3%2C%5C%20t%3D-3

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3 years ago

115.376 as hundreds tens and ones

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3 years ago

Exactly 1 1/3 yard of ribbon is needed to make a bow. Which of the following lengths of ribbon could be used to make a bow with

svp [43]

Answer:

1 and 2/5 yards wastes only 1/15 a yard

Step-by-step explanation:

1 and 1/6 yards would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/10 yards would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/5 yards

$1\frac{2}{5} -1\frac{1}{3} =\\\\1\frac{6}{15} -1\frac{5}{15} =\\\\\frac{1}{15}$

Wastes 1/15 a yard.

1 and 1/2 yards

$1\frac{1}{2} -1\frac{1}{3} =\\\\1\frac{3}{6} -1\frac{2}{6} =\\\\\frac{1}{6}$

It wastes 1/6 a yard.

2 yards

$2-1\frac{1}{3} =\frac{2}{3}$

It wastes 4/6 a yard.

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3 years ago

The weights of a large number of miniature poodles are approximately normally distributed with a mean of 8 kilograms and a stand

harina [27]

Answer and Step-by-step explanation:

Considering the table attached.

(a) over 9.5 kg;

μ = 8

σ = 0.9

z = 9.5 - 8/0.9 ≈ 1.67

P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475

(b) at most 8.6 kg;

z = 8.6-8/0.9 ≈ 0.67

P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486

z₁ = 7.3-8/0.9 ≈ -0.78

z₂ = 9.1 - 8/0.9 ≈ 1.22

P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711

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3 years ago