Ask question

Ask question

All categories

2 years ago

14

If forces are unbalanced, what will happen to the object (horse)?

1 answer:

vampirchik [111]2 years ago

3 0

Answer:

Newton's 2nd Law says that an object accelerates if there is a net (unbalanced) force on it. Looking at the wagon in the diagram above, you can see that there is just one force exerted on the wagon - the force that the horse exerts on it. The wagon accelerates because the horse pulls on it!

You might be interested in

Find the 20th term of the following sequence. -6, -4, -2, 0

posledela

Answer:

32.

Step-by-step explanation:

This is an arithmetic sequence with first term a1 = -6 and common difference 2.

an = a1 + d(n - 1)

a20 = -6 + 2(20-1) = 32

6 0

3 years ago

4. How fast was a driver going if the car left skid marks that were 32 feet long on dry concrete? (The coefficient of friction i

Monica [59]

Answer:

$v_{o} \approx 31.247\,mph$

Step-by-step explanation:

The deceleration experimented by the car is the product of kinetic coefficient of friction and gravitational constant:

$a = \mu_{k}\cdot g$

$a = (1.02)\cdot \left(32.174\,\frac{ft}{s^{2}} \right)$

$a = 32.817\,\frac{ft}{s^{2}}$

The initial speed is computed from the following kinematic expression:

$v^{2} = v_{o}^{2} - 2\cdot a \cdot \Delta s$

$v_{o} = \sqrt{v^{2}+2\cdot a\cdot \Delta s}$

$v_{o} = \sqrt{\left(0\,\frac{ft}{s} \right)^{2}+2\cdot \left(32.817\,\frac{ft}{s^{2}} \right)\cdot (32\,ft)}$

$v_{o}\approx 45.829\,\frac{ft}{s}$

$v_{o} \approx 31.247\,mph$

8 0

3 years ago

Y=x+5<br> x-5y=-9<br> Can someone please help ASAP

Dmitriy789 [7]

X = -4
Y = 1

1 = -4 + 5
-4 - 5(1) = -9

7 0

2 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint.

Shtirlitz [24]

Answer:

endpoint is (29, -13)

Step-by-step explanation:

Formula for midpoint is $(\frac{x_{1} + x_{2} }{2} ,\frac{y_{1} + y_{2} }{2} )$

So, let $(x_{2} , y_{2} )$ be the coordinates of the endpoint you are looking for.

$x_{1} = -9$ and $y_{1} = 7$

$(\frac{-9 + x_{2} }{2} , \frac{7 + y_{2} }{2} )$ = (10, -3)

$\frac{-9 + x_{2} }{2} = 10$ $\frac{7 + y_{2} }{2} = -3$

-9 + $x_{2}$ = 20 7 + $y_{2} = -6$

$x_{2} = 29$ $y_{2} = -13$

endpoint is (29, -13)

6 0

2 years ago

Which of the following is a rational number? EXPLAIN WHY FOR BRAINLIEST

Romashka-Z-Leto [24]

It’s B because it equals -8 when simplified which is a rational number

7 0

2 years ago