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babunello [35]
3 years ago
8

URGENT!!!!! With workings

Mathematics
2 answers:
Aneli [31]3 years ago
6 0
There’s probably an easier way to do it like with the equation to find the area of a trapezoid but i did it this way bc it’s easier for me

i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)

THE ANSWER IS 68.9 CM

tester [92]3 years ago
5 0

Step-by-step explanation:

please follow to the best you can paper. hope it helps

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a radio station can broadcasts in all directions to a distance of 60 mi. what is the area in which the station can be heard
zaharov [31]

Answer:

Area = PI * radius ^ 2

Area = PI * 60^2

Area = PI * 3,600

Area = 11,309.73 square miles

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
It took Brian 6 hours to drive to the sales conference. He took the same route on the way back home, but
g100num [7]

Answer:  54 mph

Step-by-step explanation:

d-the distance

s+9  -  the speed to the conference

d=6*(s+9)

s- is the speed on the way back home

d=7*s

so    6*(s+9)=7*s

       6s+54=7s

     -6s          -6s

       54= 7s-6s

       s=54  mph

6 0
3 years ago
What is the perpendicular distance from the line y= 2x-3 to the point (8,3)
Liula [17]
Find the perpendicular line then find the intersection then find the point

perpendicular lines have slopes that are perpendicular
the slopes multiply bo -1

y=mx+b
m=slope
y=2x-3
2 is slope

2 times what=-1
what=-1/2


the equation is
y-3=-1/2(x-8) or
y=(-1/2)x+7

find intersection
at (4,5)
distance bwetweeen (8,3) and (4,5)
D=\sqrt{(8-4)^2+(3-5)^2}
D=\sqrt{(4)^2+(-2)^2}
D=\sqrt{16+4}
D=\sqrt{20}
D=2√5
distance= 2√5
7 0
3 years ago
How do you simplify this?
bezimeni [28]
I can't show you the square root but this is the answer simplified. 4 square roots of 6
5 0
3 years ago
Why is 1/2 not useful as a benchmark to compare 5/8 and 9/10?
pentagon [3]
1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
4 0
3 years ago
Read 2 more answers
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