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harina [27]
3 years ago
7

John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for the n

ext 10 months. The extra cost paid by taking this deal is equivalent to what actual yearly rate of interest?
A. 3.6%
B. 63%
C. 33%
D. 36%

Please provide an explanation, thanks! :)
Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

(D) 36%

Step-by-step explanation:

Actual cost of truck = $4500

Down payment = $1500

Money left to be paid = 4500-1500 =  $3000

A = Monthly payments = 350

n = 10

Principal value (P) = 3000

Using formula,

A= \frac{Pr(1+r)^{n}}{(1+r)^{n}-1}

350 =\frac{3000r(1+r)^{10}}{(1+r)^{10}-1}

       = 36% (approx)

Hence (D) is correct.

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4 coffees and 12 lattes. Costs $61
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Answer:

Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>

Step-by-step explanation:

Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.

Given:

4 coffees and 12 lattes cost $61.

12 coffees and 7 lattes cost $59.75.

∵ 1 coffee cost = c

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Now, as per question:

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Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

-3(4c+12l)=-3(61)\\\\-12c-36l=-183\\12c+7l=59.75\\+\\----------\\0-29l=-123.25\\\\l=\frac{-123.25}{-29}=\$4.25

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

4c+12(4.25)=61\\\\4c+51=61\\\\4c=61-51\\\\4c=10\\\\c=\frac{10}{4}=\$2.5

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.

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