Q3.

Miki, a resident of Kyoto, earns an annual salary of ¥6,760,950. If the Japanese government levies a 29.12% income tax on Miki’s

ankoles [38]

Find 29.12% of 6,760,950. You can do this by converting 29.12% to a decimal by moving the decimal 2 places to the left and getting rid of the percent sign. Do this and you figure out 29.12% is .2912 as a decimal. Now you multiply this decimal with 6,760,950 to find what the government takes for taxes from his annual salary. You get 1,968,788.64. This is not your final answer because you want to find the amount of money he keeps after taxes. So you'd subtract 1,968,788.64 from 6,760,950. This gives you 4,792,161.36. This is his take-home pay, but you have to round to the nearest yen, so your final answer is 4,792,161.

7 0

3 years ago

Read 2 more answers

Can u help me on number 5,6,and 7 i will help u on what u need just send me a message

Fynjy0 [20]

5. Input 5 where the x's, 3 = 2(5) - 7 is a true statement. 10 - 7 = 3
3 < 10 - 9 is a false statement, 3 > 1 is a true statement
2 is less than or equal to 11, is a false statement (2 is less than 11, but not equal to)
18 = 30 -12 is a true statement 30 - 12 = 18, 18=18
3= 2 + 5 is a false statement, 3 is not equal to 7

6. 7 is less than or equal to 5(4) -16, 20 - 16 = 4, 7 is not less than or equal to 4. Therefore, 4 is not a solution.

7. 9(5) - 3 < 60, 45-3 < 60, 42 < 60, 42 is less than 60, so the equation is true.
9(6) - 3 < 60, 54 - 3 < 60, 51 < 60, 51 is less than 60, so the equation is true.
6(7) - 3 < 60, 63 -3 < 60, 60 < 60, 60 is equal to 60, the equation is false.

4 0

4 years ago

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The average life of a bread-making machine is 7 years, with a standard deviation of 1 year. Assuming that the lives of these mac

Alina [70]

Answer:

a) $P(6.4$

b) $a=7 +1.036*0.333=7.345$

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable life of a bread making machine. We know from the problem that the distribution for the random variable X is given by:

$X\sim N(\mu =7,\sigma =1)$

We take a sample of n=9 . That represent the sample size.

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is also normal and is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar X \sim N(\mu=7, \frac{1}{\sqrt{9}})$

Solution to the problem

Part a

(a) the probability that the mean life of a random sample of 9 such machines falls between 6.4 and 7.2

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

The standard error is given by this formula:

$Se=\frac{\sigma}{\sqrt{n}}=\frac{1}{\sqrt{9}}=0.333$

We want this probability:

$P(6.4$

Part b

b) The value of x to the right of which 15% of the means computed from random samples of size 9 would fall.

For this part we want to find a value a, such that we satisfy this condition:

$P(\bar X>a)=0.15$ (a)

$P(\bar X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.036. On this case P(Z<1.036)=0.85 and P(Z>1.036)=0.15

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.036$

And if we solve for a we got

$a=7 +1.036*0.333=7.345$

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

8 0

4 years ago

How is this solved. Ive tried different ways and cant get it

lukranit [14]

It's kinda like using variables, but shapes in their place. Let's set the circle to x, the triangle to y, and the square to z. Now the equations say x+(y+z)=13, (y+z)=8, and x+y=7. First thing we can do it plug 8 into the first equation for y+z, getting x+8=13. Subtract 8 to both sides and x (or circle) equals 5. Plug 5 into the last equation, x+y=7 to solve for y, getting 5+y=7. Subtract 5 to both sides and y (or triangle) equals 2. Finally, plug two in for y in y+z=8, getting 2+z=8. Subtract 2 from both sides and z (or square) equals 6. Hope I've explained it clearly!!

3 0

3 years ago

Why is it important to have a control group in an experiment of investigation?

AnnZ [28]

Answer:

I think its A

Step-by-step explanation:

Sorry if I'm wrong

6 0

4 years ago