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Harrizon [31]
3 years ago
5

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

a = 6

x^2 + 6x is equal to x(x+6)

b=2

Denominator and numerator of the first term are multiplied by x. 

c=6

Second term is multiplied by (x-6)/(x-6)

d=2

Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term

e=6

In the same way as d is carried over from b, e is carried over from c. 

f = 6

2x - x + 6 = x + 6

g = 1 

We factor out the (x+6) from the numerator and denominator

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=(2⋅ℎ⋅ℎ)+(2⋅ℎ⋅ℎℎ)+(2⋅ℎ⋅ℎℎ)

4 0
3 years ago
K/2+1/2=3 find the k
NikAS [45]

Answer:

k = 5

Step-by-step explanation:

Given

\frac{k}{2} + \frac{1}{2} = 3 ( multiply through by 3 to clear the fractions )

k + 1 = 6 ( subtract 1 from both sides )

k = 5

4 0
3 years ago
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Jeff wants to spend at most $89 on his mom's birthday gifts. He already bought her a
Andrew [12]

The Inequality representing money she can still spend on her friend birthday gift is .

Jordan can still spend at most $30 on her friends birthday gift.

Step-by-step explanation:

Given:

Total money need to spend at most = $45

Money spent on Yoga ball = $15

We need to find how much money she can still spend on her friend birthday gift.

Solution:

Let the money she can still spend on her friend birthday gift be 'x'.

So we can say that;

Money spent on Yoga ball plus money she can still spend on her friend birthday gift should be less than or equal to Total money need to spend.

framing in equation form we get;

The Inequality representing money she can still spend on her friend birthday gift is .

On solving the the above Inequality we get;

we will subtract both side by 15 using subtraction property of Inequality.

Hence Jordan can still spend at most $30 on her friends birthday gift.

4 0
2 years ago
The power generated by an electrical circuit (in watts) as a function of its current c (in amperes) is modeled by: P(c) = -12c^2
Ksenya-84 [330]

Answer:

The maximum power generated by the circuit is 300 watts.

Step-by-step explanation:

A quadratic function is one that can be written as an equation of the form:

f (x) = ax² + bx + c

where a, b and c (called terms) are any real numbers and a is nonzero.

In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.

The vertex is a point that is part of the parabola, which has the value as ordered  minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.

The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:

  • The value of x, in this case the value of current c in amperes, can be calculated with the formula c=\frac{-b}{2*a} . In this case: c=\frac{-120}{2*(-12)} So c= 5 amperes. The current is 5 amperes.
  • The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts

<u><em>The maximum power generated by the circuit is 300 watts.</em></u>

7 0
3 years ago
△ABC and △CDE similar right triangles. The coordinates of all the vertices are integers. The relationship between the slope of A
aleksandr82 [10.1K]

hmmmmmmmm......... is it 4?

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