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Answer:
The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is:
Step-by-step explanation:
Given points are:
(-5,3) and (3,7)
The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.
First of all we have to find the slope and mid-point of given line
Here
(x1,y1) = (-5,3)
(x2,y2) = (3,7)
The slope will be:
The mid-point will be:
Let m1 be the slope of the perpendicular bisector
Then using, "Product of slopes of perpendicular lines is -1"
We have to find the equation of a line with slope -2 and passing through (-1,5)
The slope-intercept form is given by:
Putting the point (-1,5) in the equation
The final equation is:
Hence,
The equation of perpendicular bisector of the line segment passing through (-5,3) and (3,7) is: