Wow a lot of plants but make a Mendelson Square [looks like a tic- tac -toe board (# this super large) with p and w at the top and p and w down the side. I would some how get those numbers checked out cuz generally there are only 4 squares:)
Y = -15 is the answer and blah
Answer:x-24
Step-by-step explanation:
Solve for xby simplifying both sides of the equation, then isolating the variable.
Answer:
Here we will simplify 2/50 to its simplest form and convert it to a mixed number if necessary.
In the fraction 2/50, 2 is the numerator and 50 is the denominator.
When you ask "What is 2/50 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction.
We do this by first finding the greatest common factor of 2 and 50, which is 2.
Then, we divide both 2 and 50 by the greatest common factor to get the following simplified fraction:
1/25
Therefore, this equation is true:
2/50 = 1/25
If the numerator is greater than or equal to the denominator of a fraction, then it is called an improper fraction. In that case, you could convert it into a whole number or mixed number fraction.
1/25 = Proper Fraction
Step-by-step explanation:
please mark brainliest
We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
<h3>What is the extraneous solution?</h3>
In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.
As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.
Let's suppose the equation is:
Squaring both the sides:
x + 4 = (x - 2)²
x + 4 = x² - 4x + 4
x² -5x = 0
x = 0 or x = 5
Checking for the solution by plugging in the equation;
3 = 3
2 ≠ -2
The solution x = 0 shows extraneous solution.
Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.
Learn more about the extraneous solution here:
brainly.com/question/14054707
#SPJ1
