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Vinil7 [7]
4 years ago
9

Find the volume of a right circular cone that has a height of 9 m and a base with a circumference of 19.6 m. Round your answer t

o the nearest tenth of a cubic meter.
Mathematics
2 answers:
Blizzard [7]4 years ago
6 0

Answer:

V = 91.70 cubic meters

Step-by-step explanation:

The volume of a right circular cone

V = πr^2h/3

V - volume of the cone

π - pie

r - radius of the cone

h - height of the cone

Given

h - 9m

Circumference = 19.6m

Find radius

Circumference = 2πr

r = c/2π

c - 19.6

π - 3.142

r = 19.6/ 2*3.142

= 19.6/6.284

= 3.119m

Using the volume of a right circular cone

V = πr2h/3

V = 3.142 * 3.119^2 * 9/3

= 3.142 * 9.728 * 3

= 91.6976 cubic meter

Rounding to the nearest tenth cubic meter

V = 91.70 cubic meters

den301095 [7]4 years ago
4 0

Answer:

91.7 m³

Step-by-step explanation:

V = 1/3 πr²h

2πr = 19.6

r = 19.6 / (2 x 3.14) = 3.12

V = 1/3 x 3.14 x 3.12² x 9 = 91.7

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Sliva [168]

Answer:

336in^3

Step-by-step explanation:

The volume of a rectangulur prism can be found by multiplying the length of the box with its height and width.

Thus, we can find the volume using the solution below:

v=l*w*h

l = 12in

h = 7in

w = 4in

12*7*4 = 336in^3

6 0
3 years ago
Two similar solid shapes a and b are shown, the solids are made from the same matierial the surface area of b is 40.32cm^2 and a
Kisachek [45]

Answer:

4000g

Step-by-step explanation:

7 0
3 years ago
Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}
Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3>   </h3>
  • To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by \large \sf a^{n}. The terms of a power are:

<h3>     </h3>
  • Base
  • Exponent
  • equal factors
  • power
<h3>         </h3>

✏️ <u>Resolution/Answer</u>:

\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\

  • Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\

  • <em>Multiply </em>the power at denominator of the fraction:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\

  • <em>Multiply </em>the numerator numbers together:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=

\large \sf \dfrac{-16\cdot16\cdot 256     }{16}=

\large \sf \dfrac{-256\cdot 256     }{16}=

\large \sf \dfrac{- 65536  }{16}=\\\\

  • Simplify the fraction by number 16:

\\\large \sf \dfrac{- 65536  }{16}=

\large \sf \dfrac{- 65536  \div16}{16\div16}=

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}} \\\\\\

  • So this expression in its simplified form = -4096/1 or -4096.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}}\\\\

                                 ★ Hope this helps! ❤️

6 0
3 years ago
Find the surface area of the pyramid
cricket20 [7]

Answer:

32√3

Step-by-step explanation:

I hope this helps... if not i dont know then

7 0
3 years ago
If 8,a,b,27 are in geometric sequence, find the value of a and b.​
wel

Answer:

a = 12 and b = 18

Step-by-step explanation:

Given that,

8,a,b,27 are in geometric sequence.

For a GP, the nth term is given by :

a_n=ar^{n-1}

Put n = 4

a_4=ar^{4-1}\\\\a_4=ar^3\\\\27=8\times r^3\\\\r^3=\dfrac{27}{8}\\\\r=\dfrac{3}{2}=1.5

Put n = 2,

a_2=ar^{2-1}\\\\a=ar\\\\a=8\times 1.5\\\\a=12

Put n = 3

a_3=ar^2\\\\=8\times 1.5^2\\\\b =18

So, the values of a and b is 12 and 18 respectively.

3 0
3 years ago
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