The problem ask to calculate the corresponding distance on the new patio where as the the patio will have two long parallel side and an area of 360 square feet and the area of the similar patio is 250 square feet and its long parallel sides are 12.5 feet apart. To calculate this the ratio of the distance of the two polygon is P:Q so it means that the are is also P^2:Q^2 so the ratio of the area is 36:25 so the the distance of the new patio is 18 feet
Answer:
n = the first
n + 1 = the 2nd
n + 2 = the 3rd
n(n + 2) - (n + 1) = 10(n + 2) + 1
n2 + 2n - n - 1 = 10n + 20 + 1
n2 - 9n - 22 = 0
(n - 11)(n + 2) = 0
If two factors = 0, at least one must = 0.
n - 11 = 0
n = 11
11,12,13
n + 2 = 0
n = -2
-2,-1,0
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.





b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.





c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.




3.6 / 0.2 = 18 liter glasses :))