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grigory [225]
3 years ago
7

Find the principal.

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

7,250.

Step-by-step explanation:

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Angle BAC measures 56°.
wel

Answer:

56

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the common difference of the following sequence.​
Darya [45]

You have the correct answer. It is choice B) -1/4

=======================================================

Explanation:

This is because we're adding -1/4 to each term to get the next one. In other words, we're subtracting 1/4 from each term to get the next one.

  • term2 = term1+(d) = 1/2 + (-1/4) = 1/2 - 1/4 = 2/4 - 1/4 = 1/4
  • term3 = term2+(d) = 1/4 + (-1/4) = 1/4 - 1/4 = 0
  • term4 = term3+(d) = 0 + (-1/4) = 0 - 1/4 = -1/4
  • term5 = term4+(d) = -1/4 + (-1/4) = -2/4 = -1/2

and so on.

----------

To find the common difference, all we have to do is subtract any term from its previous one.

For example:

d = (term2) - (term1)

d = (1/4) - (1/2)

d = (1/4) - (2/4)

d = (1-2)/4

d = -1/4

The order of subtraction matters, so we cannot say d = term1-term2.

3 0
2 years ago
Which unit rate corresponds to the proportional relationship shown in the graph?
Y_Kistochka [10]
To move from the point (0,0) to the point (6,9) we move up 9 units and right 6 units.

Slope = rise/run
Slope = change in y / change in x
Slope = 9 / 6
Slope = 3/2
6 0
2 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
I need with #10, please?
777dan777 [17]

Answer:

h=7ft

Step-by-step explanation:

sinФ=opposite/hypotenuse

sin45°=5/h

0.71=5/h

multiply via by h

0.71h=(5/h)h

h cancel h it remains 5

0.71h=5

divide through by 0.71

0.71h/0.71=5/0.71

h=7.04ft

h=7ft approximately



4 0
3 years ago
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