Answer:
56
Step-by-step explanation:
You have the correct answer. It is choice B) -1/4
=======================================================
Explanation:
This is because we're adding -1/4 to each term to get the next one. In other words, we're subtracting 1/4 from each term to get the next one.
- term2 = term1+(d) = 1/2 + (-1/4) = 1/2 - 1/4 = 2/4 - 1/4 = 1/4
- term3 = term2+(d) = 1/4 + (-1/4) = 1/4 - 1/4 = 0
- term4 = term3+(d) = 0 + (-1/4) = 0 - 1/4 = -1/4
- term5 = term4+(d) = -1/4 + (-1/4) = -2/4 = -1/2
and so on.
----------
To find the common difference, all we have to do is subtract any term from its previous one.
For example:
d = (term2) - (term1)
d = (1/4) - (1/2)
d = (1/4) - (2/4)
d = (1-2)/4
d = -1/4
The order of subtraction matters, so we cannot say d = term1-term2.
To move from the point (0,0) to the point (6,9) we move up 9 units and right 6 units.
Slope = rise/run
Slope = change in y / change in x
Slope = 9 / 6
Slope = 3/2
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is
Step-by-step explanation:
From the question we are told that
The upper specification is 
The lower specification is
The sample mean is
The standard deviation is 
Generally the capability index in mathematically represented as
![Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7BUSL%20-%20%20%5Cmu%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%20%2C%20%20%5Cfrac%7B%5Cmu%20-%20LSL%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%5D)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
![Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7B1.68%20-%20%201.6%20%7D%7B%203%20%2A%20%200.03%20%7D%20%20%2C%20%20%5Cfrac%7B1.60%20-%20%201.52%20%7D%7B%203%20%2A%20%200.03%7D%20%5D)
=> ![Cpk = min[ 0.88 , 0.88 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%200.88%20%2C%200.88%20%20%5D)
So

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that

So

=> 
=> 
So

=> 
Hence
![Cpk = min[ 2, 2 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%202%2C%202%20%5D)
So

So
is the value of standard deviation required
Answer:
h=7ft
Step-by-step explanation:
sinФ=opposite/hypotenuse
sin45°=5/h
0.71=5/h
multiply via by h
0.71h=(5/h)h
h cancel h it remains 5
0.71h=5
divide through by 0.71
0.71h/0.71=5/0.71
h=7.04ft
h=7ft approximately