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Xelga [282]
3 years ago
6

The demon drop at cedar point in Ohio takes riders to the top of a tower and drops them 60 feet. A function that approximates th

is ride is h = 16^2 + 64x - 60, where h is the height in feet t
Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Completion of question:

The Demon Drop at Cedar point in Ohio takes riders to the top of the tower and drops them 60 feet. A function that approximates this ride is h=-16^t2 + 64t + 60 where h is the height in feet and t is the time in seconds. About how many seconds does it take for riders to drop to the ground?

Answer:

4.78 s

Step-by-step explanation:

Given the equation :

h = - 16^t2 + 64t + 60

Using the quadratic formula ; where

a = - 16 ; b = 64 ; c = 60

Dropping to the ground, h = 0

16^t2 + 64t - 60 = 0

-b ± (√b²- 4ac) / 2a

-64 ± (√64²- 4(-16)(60)) / 2(-16)

-64 ± (√7936) / - 32

(-64 ± 89.08) / - 32

(-64 + 89.08) / - 32 = - 0.783 OR

(-64 - 89.08) / - 32 = 4.78

Reject the negative

t = 0.783 seconds

Thomas Kyle
3 years ago
What about the given; h=60 ? Since h = −16t² + 64t + 60, so; 60 = −16t² + 64t + 60 ..
Thomas Kyle
3 years ago
So; −16t² + 64t + 60 - 60 = 0
Thomas Kyle
3 years ago
−16t² + 64t + 0 = 0
Thomas Kyle
3 years ago
-64 ± (√64²- 4(-16)(0)) / 2(-16) ; (-64 ± √64²) /-32 ; -128/-32 or 0/-32 ; Answer: 4
Thomas Kyle
3 years ago
Check me if I'm wrong .. Cheers!
Thomas Kyle
3 years ago
Nope I'm wrong. I should equate that to = 0 as it's the time taken to reach 0 from 60. Cheers again! :)
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