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8090 [49]
3 years ago
11

(3x + 1/2 ) + ( 7x - 4 1/2 ) simply the expression

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0

(3x + 1/2 ) + ( 7x - 4 1/2 )

3x+7x + 1/2 - 4 1/2

10x -4

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Please help, PhotoMath isn’t helping and I don’t understand
Pie

Answer:

Option B

Step-by-step explanation:

As here,

In all the options processes in 3rd step .

<u>As</u><u> </u><u>the</u><u> </u><u>bases</u><u> </u><u>are</u><u> </u><u>same</u><u> </u><u>exponents</u><u> </u><u>get</u><u> </u><u>added</u><u>. </u>

And in Option B 3rd step it has been correctly done form of,

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Is correct simplification.

4 0
2 years ago
Write the prime factorization for 168
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168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7
7 0
3 years ago
Find the measure of the indicated angle to the nearest degree​
sweet-ann [11.9K]

Answer:

Im pretty sure its 45 degrees

Step-by-step explanation:

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5 0
2 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

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$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
NEED HELP FAST PLZ!!
Rudik [331]

Answer:

no clue

Step-by-step explanation:

!!!!!!!!!!!

8 0
2 years ago
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