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iragen [17]
3 years ago
11

Solve the System of Equations using the substitution method. -5x-3y=16 y=x

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0
According to the second equation, “x” is equal to “y.” With this knowledge, we can substitute the value “x” into the first equation:

-5x – 3y = 16
-5x – 3(x) = 16

Combine like terms:

-8x = 16

Divide (-8) from both sides of the equation:

x = -2

We have proven that “x” is equal to (-2). Using this knowledge, we can now substitute the known value of “x” into the second equation:

y = x
y = (-2)

We have now proven the values of both X and Y:

x = -2
y = -2

I hope this helps!
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Which two integers is √56 between?<br> Please help me.
lozanna [386]

Answer:

7 and 8.

Step-by-step explanation:

When we check out what is √49 and √64, we can see that they equal 7 and 8 respectively. Since √56 is between √49 and √64, we can say that √56 is between 7 and 8.

Hoped this helped.

8 0
3 years ago
The product of a number and 9, increased by 4, is 58. Find the number.
diamong [38]
9x + 4 = 58
9x = 54
x = 6

The number is 6.
4 0
4 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t
damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0
3 years ago
17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
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Arturiano [62]
Answer: 2/15
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8 0
3 years ago
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