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Illusion [34]
3 years ago
6

The equation y = 14x/z represents _____________ variation.

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

D. joint variation

Step-by-step explanation:

y = 14x/z

y is directly proportional to x and inversely proportional to y

Constant of proportionality = 14

Direct variation is given as

y = kx

Where, k = constant of proportionality

Inverse variation is given as

y = k/z

Where, k = constant of proportionality

When they are jointly combined

y = kx/z

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Write an equation that represents the line.
Fynjy0 [20]

Answer:

Y = 2/3X + 4/3

Step-by-step explanation:

(1,2) (4,4)

M = 2/3

Y = 2/3X + b

4 = 8/3 + b

12 = 8 + 3b

4 = 3b

B = 4/3

Y = 2/3X + 4/3

4 0
3 years ago
Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.
Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0
3 years ago
I have a test tomorrow
Nana76 [90]

well i wish you the best of luck buddy

5 0
4 years ago
Read 2 more answers
In the figure, the ratio of the perimeter of rectangle ABDE to the perimeter of triangle BCD is . The area of polygon ABCDE is s
Gekata [30.6K]

Step 1

Find the perimeter of rectangle ABDE

we know that

the perimeter of rectangle is equal to

P=2b+2h

In this problem

b=ED=2\ units

h=AE=6\ units

substitute

P=2*2+2*6=16\ units  

Step 2

Find the perimeter of triangle BCD

we know that

the perimeter of triangle is equal to

P=BD+DC+BC

In this problem we have

BD=AE=6\ units

DC=BC

Applying the Pythagoras theorem

DC^{2}=4^{2}+3^{2}

DC^{2}=25

DC=5\ units

substitute

P=6+5+5=16\ units

Find the ratio of the perimeter of rectangle ABDE to the perimeter of triangle BCD

we have

the perimeter of rectangle is equal to

P=16\ units  

the perimeter of the triangle is

P=16\ units  

so

the ratio is equal to

\frac{16}{16} =1

therefore

<u>the answer Part 1) is the option B</u>

1

Step 3

Find the area of polygon ABCDE

we know that

The area of polygon is equal to the sum of the area of rectangle plus the area of triangle

Area of rectangle is equal to

A=AE*BD=6*2=12\ units^{2}

Area of the triangle is equal to

A=\frac{1}{2}AEh

the height h of the triangle is equal to 4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of polygon is

12\ units^{2}+12\ units^{2}=24\ units^{2}

therefore

<u>the answer part 2) is the option C</u>

24\ units^{2}


7 0
4 years ago
Read 2 more answers
5th grade math. correct answer will be marked brainliest.
FinnZ [79.3K]

Answer:

DBCWBSHCHCVGCHWYEFDWEXBSAJNWUGDIHVBSYXVP VDXCBBVXBSGGSHYSXULSOOSKBHSOLSHOLSFHOJDKFIHEJIFWUGUJH

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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