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Natali5045456 [20]
3 years ago
8

A coach needs both small and large cones to set up an obstacle course. He knows there are fewer than 30 cones in the storage roo

m. He needs at least a dozen large cones. Let x represent the number of small cones and y represent the number of large cones.
Which inequalities model the situation?

Choose exactly three answers that are correct.
(Points : 1)
x + y < 30
x + y ≤ 30
y > 12
y ≥ 12
x > 0
x ≥ 0
Mathematics
1 answer:
ratelena [41]3 years ago
7 0
I think it is the first one. Hope it helps! :)
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1. If y<span>ou have jogged 5 miles from the park at a rate of r miles per hour, then the time you need to do this is \frac{5}{r} hours (S=v\cdot t, where S is distance, v-speed and t-time).
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2. W<span>hen you run back to the park, your average speed increases by 1 mph and become r+1 mph.
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3. I<span>t takes \frac{5}{r+1} hours to jog 5 miles back to the park</span>

4. T<span>he total jogging time T is \frac{5}{r} + \frac{5}{r+1} hours.</span>
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5. If you jogged away from the park at an average speed of 4 miles per hour, then r+1=4 and r=3. The expression \frac{5}{r} + \frac{5}{r+1}will take look 
<span>\frac{5}{3} + \frac{5}{4}=\frac{5\cdot4+5\cdot 3}{12} =\frac{35}{12}=2.9hours.</span>



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3 years ago
For babysitting, Nicole charges a flat fee of $3, plus $5 per hour. Write an equation for the
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3 + 5h = c
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The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the prob
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Larry is measuring the volume of a pitcher. He uses a measuring cup that holds 2 cups and fills the measuring cup 7.5 times to f
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Given,

The amount of liquid hold by measuring cup is 2 cups.

The number of times measuring cup used to fill the pitcher.

Required:

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The amount of liquid hold by the pitcher is,

Amount\text{ of liquid = number of times measuring cups used}\times amount\text{ of liquid hold by measuring cup}

Substituting the values.

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1 year ago
pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​
yanalaym [24]

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

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now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

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