We are given a tasked to find the geometric property of a triangle that satisfies the given conditionm∠abc=m∠cbd, then m∠cbd=m∠abc.
It can be observed that if the first value is equal to the second value then the second value is also equal to the first value. This kind of characteristics describes the Symmetric Property.
X^2 - 13 x = -36
add 36 to both sides
x^2 - 13x +36 = 0
figure out the factor
(x-4)(x-9) = 0
so (x-4) or (x-9) equals 0
so solution is
x-4=0 add 4 to both sides and get x = 4
x-9=0 add 9 to both sides and get x=9
x={ 4, 9}
Answer:
Step-by-step explanation:
line graph- the decrease of attendance
bar graph-the number of students who participate in different sports
line plot-the list of heights of a group of 80 adults
steam and leaf plot- the number of dogs for students
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
Answer:
the best option would be to swim
Step-by-step explanation:
Hello! To solve this problem we must follow the following steps.
1. remember the concept of uniform motion with constant speed, which establishes the following equation

where
t=time
x=distance
V=speed
2. Calculate the time it takes to swim and calculate the time it takes to walk
walking:
x=10mile
v=5milles/h

swimming
x=1mile
v=3milles/h

3. Compare both results and choose the one with the least time.
as you can see it takes less time swimming, so this would be the best way