What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
1 answer:
Answer:
i. 9
ii. 14
iii. 405
iv.
Step-by-step explanation:
The number of diagonals in a polygon of n sides can be determined by:
where n is the number of its sides.
i. For a hexagon which has 6 sides,
number of diagonals =
=
= 9
The number of diagonals in a hexagon is 9.
ii. For a heptagon which has 7 sides,
number of diagonals =
=
= 14
The number of diagonals in a heptagon is 14.
iii. For a 30-gon;
number of diagonals =
=
= 405
The number of diagonals in a 30-gon is 405.
iv. For a n-gon,
number of diagonals =
The number of diagonals in a n-gon is
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Hi here’s the answers hope this helps
Answer:
C -1
Step-by-step explanation:
Answer as a compound inequality:
Answer in interval notation: [-4, 2)
=============================================
Explanation:
The range is the set of all possible y outputs of a function. When dealing with a graph like this, we just look at the highest and lowest points to determine which y values are possible.
The lowest point occurs when y = -4. We include this value. So far we have which is the same as
The upper ceiling for the y value is y = 2. We can't actually reach this value because of the open hole at (-3,2). So we say that
Combine and
to get the compound inequality
This says y is between -4 and 2, including -4 but excluding 2.
To convert this to interval notation, we write [-4, 2) where the square bracket says to include the endpoint and the curved parenthesis says to exclude the endpoint.