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Afina-wow [57]
3 years ago
6

1. Write the exponential function f(x) = -4^(x-2) in the form f(x) = ab^x​

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

\displaystyle f(x)=-\frac{1}{16}(4^x)

Step-by-step explanation:

We have the function:

f(x)=-4^{x-2}

And we want to convert this to the exponential form:

f(x)=ab^x

First, using the power of a product property, we can rewrite our function as:

f(x)=-(4^x\cdot4^{-2})

By evaluating the second term, we acquire:

\displaystyle f(x)=-\big(4^x\cdot \frac{1}{4}^2}\big)=-\big(4^x\cdot \frac{1}{16}\big)

So, by rearranging, we acquire:

\displaystyle f(x)=-\frac{1}{16}(4^x)

As desired.

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2.52 + 12 = 1.25z + 24<br> 16.9
frez [133]

Answer:

OK So i didnt know if it was +16.9 so the first answer i got i didn't add the 16.9 and i got z= -7.584 then when i did it with the 16.9 i got z= -21.104

Step-by-step explanation:

6 0
3 years ago
Solve for x. have to turn in by tomorrow !
Mademuasel [1]
You'll do the (whole)(outside)= (whole)(outside) so, set it up like this: (5+3)3= (x+4)4now work it out with PEMDAS: 15+9=4x+16combine like terms: 24= 4x+16subtract the 16 from each side: 8=4xlastly, divide by 4 on each side to get x=2

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4 years ago
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
-4.3&lt;-2.91&lt;5.7 <br>is that that true?
IRISSAK [1]
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7 0
3 years ago
[30 POINTS] Please help!!!
Len [333]

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-2=1.5(x+2)

y=1.5x+3+2

y=1.5x+5

Part 2) we know that  

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

the slope of the line 1 is equal to

m1=1.5

Find the slope m2

1.5*m2=-1

m2=-2/3

Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

y=-(2/3)x-(14/3)+1

y=-(2/3)x-(11/3)

Part 3) we have

m=1/4=0.25

point(1,3)  

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-3=0.25(x-1)

y=0.25x-0.25+3

y=0.25x+2.75

Part 4) we have

m=-2

b=5 -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

y=mx+b

substitute the values

y=-2x+5

Part 5) we have that

The slope of the line 4 is equal to -2

so

the slope of the line perpendicular to the line 4 is equal to

-2*m=-1\\m=(1/2)=0.5

therefore

in this problem we have

m=0.5

point(-2,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

y=0.5x+1-2

y=0.5x-1

Part 6)

using a graphing tool

see the attached figure

3 0
3 years ago
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